brackets

问题 I have the following strings: 1 "R J BRUCE & OTHERS V B J & W L A EDWARDS And Ors CA CA19/02 27 February 2003", 2 "H v DIRECTOR OF PROCEEDINGS [2014] NZHC 1031 [16 May 2014]", 3 '''GREGORY LANCASTER AND JOHN HENRY HUNTER V CULLEN INVESTMENTS LIMITED AND ERIC JOHN WATSON CA CA51/03 26 May 2003''' I am trying to find a regular expression which matches all of them. I don't know how to match optional square brackets around the date at the end of the string eg [16 May 2014]. casename = re.compile

问题 I can't seem to find a way to select the beginning of a bracket and jump to the end of it through some key combination or something in VS Code . For example, in atom , this is done with Ctrl + m . I know there is a way to jump to the beginning and end of a bracket or curlybraces with Cmd + Shift + \ but that does not work for tags. Any ideas? 回答1: It is possible to do, but either using Ctrl + Shift + P -> " Emmet: Go to Matching Pair " or by manually setting a shortcut for it ( Ctrl + K Ctrl

问题 I have a master branch: Then I make employee branch from the master and change it a bit: And when I swipe between branches, the master branch also had been changed: I have no clue why it happens. Any suggestions how to return it back to norm? 回答1: When you make a change in your editor, you only modify the code in your "working directory". When you switch branches, those changes in your "dirty" directory come along for the ride. Once you commit your changes on a given branch, switching

问题 I am having trouble understanding the usage of brackets in "for" loops and "if" statements in Javascript. I have seen syntax in Javascript where there is brackets and where there isn't. I was told that generally one should use the brackets. Can someone clearly explain when we should use brackets for "for" and "if" loops? function range(upto) { var result = []; for (var i = 0; i <= upto; i++) result[i] = i; return result; } console.log(range(15)); The result of this would be [0, 1, 2, 3, 4, 5,

问题 What is the difference in these two statements in python? var = foo.bar and var = [foo.bar] I think it is making var into a list containing foo.bar but I am unsure. Also if this is the behavior and foo.bar is already a list what do you get in each case? For example: if foo.bar = [1, 2] would I get this? var = foo.bar #[1, 2] and var = [foo.bar] #[[1,2]] where [1,2] is the first element in a multidimensional list 回答1: [] is an empty list. [foo.bar] is creating a new list ( [] ) with foo.bar as

问题 def colarray=[] def num def newRole = rolecol.split(',') def len = newRole.size() println "$newRole,$len" for (num = 0; num < len; num++) { def col = "col" col="$col"+newRole[num] colarray.add(col) } println colarray sql.eachRow("select col01,$colarray from read_csv where col01=? and col${usercol}!=? ", [file.name,""]) i want save col1..col11 into array and call it from select statement, but the problem is that $colarray has the brackets with it (like [col03, col04, col05, col06, col07, col08

问题 I'm doing some homework for a shell scripting class and had a question asking me to write a script that tests whether or not the argument entered is a valid shell variable name. The below script seems to work fine. if echo "$1" | grep -v ".*[^A-Za-z_]" > /dev/null then echo yes else echo no fi I understand brackets are short hand for the test function in the BASH shell. My problem is that, when I attempted the above script using brackets I got an error. if [ echo "$1" | grep -v ".*[^A-Za-z_]"

问题 How to change color of brackets when they are selected ? 回答1: Go over to Settings, and then just go to this menu: 回答2: Maybe the plugin HighlightBracketPair is suitable for you. The plugin will highlight the most left and most right brace pair for you when you move the caret, and you can custom the color the effect. Java Highlight Go Highlight Config Page 回答3: File => Settings => Editor => Color Scheme => General => Code => Matched brace 来源： https://stackoverflow.com/questions/21259635

问题 What does it mean when their are square brackets in front of double . For example double[] and is there any special way to use the return function when using them in a method. For Example: public double[] MethodName(){ } What is the type of the return value? 回答1: Square brackets [] would indicate an array. In your case of code: public double[] MethodName(){ .... } You have a public method MethodName which returns an array. Double indicates what type the array is, i.e. stores an array of

问题 I have a string that i am want to remove punctuation from. I started with sed 's/[[:punct:]]/ /g' But i had problems on HP-UX not liking that all the time, and some times i would get a 0 and anything after a $ in my string would dissappear. So i decided to try to do it manually. I have the following code which works on all my punctuation that I am interested in, except I cannot seem to add square brackets "[]" to my sed with anything else, otherwise it does not replace anything, and i dont