assign

问题 I am trying to assign the value of this stucture path to a fieldsymbol, but this path does not work because it has a table in it's path. But with in the debugger this value of this path is shown correctly. Is there a way to dynamically assign a component of a table line to a fieldsymbol, by passing one path? If not then I will just read the table line and then use the path to get the wanted value. ls_struct (Struct) - SUPPLYCHAINTRADETRANSACTION (Struct) - INCL_SUPP_CHAIN_ITEM (Table) -

问题 I am trying to assign the value of this stucture path to a fieldsymbol, but this path does not work because it has a table in it's path. But with in the debugger this value of this path is shown correctly. Is there a way to dynamically assign a component of a table line to a fieldsymbol, by passing one path? If not then I will just read the table line and then use the path to get the wanted value. ls_struct (Struct) - SUPPLYCHAINTRADETRANSACTION (Struct) - INCL_SUPP_CHAIN_ITEM (Table) -

问题 I'm new in tensorflow and I'm trying to understand its behaviors; I'm trying to define all the operations outside the session scope so to optimize the computation time. In the following code: import tensorflow as tf import numpy as np Z_tensor = tf.Variable(np.float32( np.zeros((1, 10)) ), name="Z_tensor") Z_np = np.zeros((1,10)) update_Z = tf.assign(Z_tensor, Z_np) Z_np[0][2:4] = 4 with tf.Session() as sess: sess.run(Z_tensor.initializer) print(Z_tensor.eval()) print(update_Z.eval(session

问题 This question already has answers here : List of lists changes reflected across sublists unexpectedly (13 answers) Closed 2 years ago . Why couldn't the first element but the whole column be updated below? >>> x=2*[2*[1]] >>> x [[1, 1], [1, 1]] >>> x[0][0]=2 >>> x [[2, 1], [2, 1]] 回答1: Even tho this is a clear duplicate but use range : >>> x=[[1 for i in range(2)] for x in range(2)] >>> x [[1, 1], [1, 1]] >>> x[0][0]=2 >>> x [[2, 1], [1, 1]] >>> At least still able to do: >>> x=[[1]*2 for x

问题 This question already has answers here : List of lists changes reflected across sublists unexpectedly (13 answers) Closed 2 years ago . Why couldn't the first element but the whole column be updated below? >>> x=2*[2*[1]] >>> x [[1, 1], [1, 1]] >>> x[0][0]=2 >>> x [[2, 1], [2, 1]] 回答1: Even tho this is a clear duplicate but use range : >>> x=[[1 for i in range(2)] for x in range(2)] >>> x [[1, 1], [1, 1]] >>> x[0][0]=2 >>> x [[2, 1], [1, 1]] >>> At least still able to do: >>> x=[[1]*2 for x

问题 Take a simple nested list L : L <- list(lev1 = list(lev2 = c("bit1","bit2")), other=list(yep=1)) L #$lev1 #$lev1$lev2 #[1] "bit1" "bit2" # # #$other #$other$yep #[1] 1 And a vector giving a series of depths for each part I want to select from L : sel <- c("lev1","lev2") The result I want when indexing is: L[["lev1"]][["lev2"]] #[1] "bit1" "bit2" Which I can generalise using Reduce like so: Reduce(`[[`, sel, init=L) #[1] "bit1" "bit2" Now, I want to extend this logic to do a replacement, like

问题 set.seed(8) df <- data.frame(n = rnorm(5,1), m = rnorm(5,0), l = factor(LETTERS[1:5])) Have can I make a new column in df conditioned on values or combination of values of n, m and l. For instance make a vector level and assign it low , medium and high based on values of both n and m (pseudo-code): df$level <- ifelse(df$n < 1 & df$m < 1, "low", ifelse(df$n > 1 & df$m > 1, "high", "medium") This should give: df$level #low medium low low medium Or if I would like to assign a value to level

问题 set.seed(8) df <- data.frame(n = rnorm(5,1), m = rnorm(5,0), l = factor(LETTERS[1:5])) Have can I make a new column in df conditioned on values or combination of values of n, m and l. For instance make a vector level and assign it low , medium and high based on values of both n and m (pseudo-code): df$level <- ifelse(df$n < 1 & df$m < 1, "low", ifelse(df$n > 1 & df$m > 1, "high", "medium") This should give: df$level #low medium low low medium Or if I would like to assign a value to level

问题 According to this answer https://stackoverflow.com/a/12020435/562222 , assigning an object to another is just copying references, but let's see this code snippet: public class TestJava { public static void main(String[] args) throws IOException { { Integer x; Integer y = 223432; x = y; x += 23; System.out.println(x); System.out.println(y); } { Integer[] x; Integer[] y = {1,2, 3, 4, 5}; x = y; x[0] += 10; printArray(x); printArray(y); } } public static <T> void printArray(T[] inputArray) { for

问题 I produced a large data frame (1700+obs,159 variables) with a function that collects info from a website. Usually, the function finds numeric values for some columns, and thus they're numeric. Sometimes, however, it finds some text, and converts the whole column to text. I have one df whose column classes are correct, and I would like to "paste" those classes to a new, incorrect df. Say, for example: dfCorrect<-data.frame(x=c(1,2,3,4),y=as.factor(c("a","b","c","d")),z=c("bar","foo","dat","dot