decoder

问题 Since MJPEG over http consists basically on the transmission of a series of JPEG images seperated by a defined seperator, how does MPlayer recognize that it is an MJPEG stream? Thank you 回答1: Have a look at: MplayerMjpegStreamViewing < Motion < Foswiki e.g. mplayer -fps 4 -demuxer lavf http://rpi-6:8080/?action=stream does the job for me. Suitable for a streaming server running on a Raspberry like this: /usr/local/bin/mjpg_streamer -o output_http.so -w ./www -i input_raspicam.so -x 1920 -y

问题 I want to concatinate 4 different videos of 4 different resolution and type into 1 video which can be played in android. I am using ffmpeg ported on android using https://github.com/guardianproject/android-ffmpeg So I have these 4 different types of videos 1) ./ffmpeg -i 1.mp4 Video: h264 (High), yuv420p, 1920x1080, 16959 kb/s, 29.85 fps, 90k tbr, 90k tbn, 180k tbc Audio: aac, 48000 Hz, stereo, s16, 106 kb/s 2) ffmpeg -i 2.mp4 Video: h264 (Constrained Baseline), yuv420p, 640x480, 3102 kb/s,

来源： https://stackoverflow.com/questions/64598849/potential-bug-with-json-decoder-swift

问题 had a look for something like this, but can't find the exact issue. I have a JSON back from server side validation that looks like: { "field": ["field-name"], "messages":["message","message"] } What I would like to do is decode it into an elm record like { field: String, messages: List String } However, I'm having trouble with the err, field field. I'm having trouble turning a single element JSON array into just a string of that element. Is it even possible with Decode, or am I better of

问题 During training, the architecture generates three models and now encoder is used to encode images with iterations=16. After performing 6 iteration, i got an error. "CUDA out of memory". I have 4 gpus and i also implemented dataparallel class but it does not work Transformation while training train_transform = transforms.Compose([ #transforms.RandomCrop((32, 32)), transforms.ToPILImage(), transforms.Resize((512, 512)), #transforms.ColorJitter(brightness=0.5), transforms.ToTensor(), ]) Encoder

问题 I've tested on Nexus 5 that codecInfo.isFeatureSupported(MediaCodecInfo.CodecCapabilities.FEATURE_AdaptivePlayback) returns false. Does anyone know what chipset/software codec has supported the feature? https://developer.android.com/reference/android/media/MediaCodecInfo.CodecCapabilities.html#FEATURE_AdaptivePlayback Thanks 回答1: This is supported on most Nexus devices past KK MR1. Note, that it is HW video decoders only. Nexus 5 (KK MR1): // Qualcomm Snapdragon 800 OMX.qcom.video.decoder.avc

问题 I starting to implement custum video decoder that utilize cuda HW decoder to generate YUV frame for next to encode it. How can I fill "CUVIDPICPARAMS" struc ??? Is it possible? My algorithm are: For get video stream packet I'm use ffmpeg-dev libs avcodec, avformat... My steps: 1) Open input file: avformat_open_input(&ff_formatContext,in_filename,nullptr,nullptr); 2) Get video stream property's: avformat_find_stream_info(ff_formatContext,nullptr); 3) Get video stream: ff_video_stream=ff

问题 I'm using VirtualDub and I want to digitalize a VHS movie frame by frame. But I need a codec which supports intra-frames. Do the following codecs supports intra-frame? If not where can I get or buy a codec with intra-frame? 回答1: From your current choices: Lagarith may be ok Xvid can be set to intra mode but this is somewhat pointless. There is a lot of better free codecs. utvideo and magicyuv are excellent lossless intra codecs. cineform is very good lossy intra codec but somewhat more

问题 If I have a certain tagged union type, like Shape here, how would I construct a JSON decoder for it in Elm? type alias Rectangle = { width : Int, height : Int } type alias Circle = { radius: Int } type Shape = ShapeRectangle Rectangle | ShapeCircle Circle 回答1: Given your JSON looks like { "radius" : 10 } or { "width" : 20, "height" : 15} Then this will do the trick import Json.Decode as Json exposing ((:=)) decodeShape : Json.Decoder Shape decodeShape = Json.oneOf [ decodeShapeRectangle ,

问题 I try to write a base64 png image to file with following code: imageReader := base64.NewDecoder(base64.StdEncoding, strings.NewReader(Images[i])) pngImage, _, err := image.Decode(imageReader) if err != nil { beego.Error(err) } bounds := pngImage.Bounds() if imgFile, err = os.Create(fileName + ".png"); err != nil { return Data{} } defer imgFile.Close() _, err = imgFile.Write([]byte(pngImage)) The bounds are ok. The error message for the last line is cannot convert pngImage (type image.Image)