Can params passed to pytest fixture be passed in as a variable?

问题:

I have two simple test setups and I'm trying to group them in one fixture and want the test function to pass in the 'params' to the fixture.

Here's a contrived example, to explain my question. Say I have the following pytest fixture:

@pytest.fixture(scope="module", params=['param1','param2']) def myFixture(request):     if request.param == 'param1':         p = 5     elif request.param == 'param2':         p = 10     return p  # would like to set request.param = ['param1'] for myFixture def test_madeup(myFixture):     assert myFixture == 5  # would like to set request.param = ['param2'] for myFixture def test_madeup2(myFixture):     assert myFixture == 10 

Can I make it so that the params above are passed in as an input to the test_madeup function? So, something like the following:

@pytest.fixture(scope="module", params=fixtureParams) def myFixture(request):     if request.param == 'param1':         return 5     elif request.param == 'param2':         return 10   def test_madeup(myFixture, ['param1']):     assert myFixture == 5 

The above, of course, doesn't work. The real case is a bit more complex, but I just want to know if I can pass the params=['param1','param2'] to the fixture from the test_madeup function.

回答1:

If i understand your question correctly, you basically want to select one instance of a parametrized fixture for executing with a test, by providing some info with the test. It's not possible although we could probably think about a mechanism. I am not sure if the following solution maps to your whole problem, but here is one way to solve the above concrete case:

import pytest  @pytest.fixture(scope="module") def myFixture1():     return 5  @pytest.fixture(scope="module") def myFixture2():     return 2  @pytest.fixture(scope="module", params=["param1", "param2"]) def myFixture(request):     if request.param == 'param1':         return request.getfuncargvalue("myFixture1")     elif request.param == 'param2':         return request.getfuncargvalue("myFixture2")  def test_1(myFixture1):     assert myFixture1 == 5  def test_2(myFixture2):     assert myFixture2 == 2  def test_all(myFixture):     assert myFixture in (2,5) 

This runs four tests, because the test_all is executed twice with both fixtures.

If the setup of your fixtures is not heavy, you might also have one fixture that produces a list and an "iterating" parametrized one. A test could then grab the whole list and index it into it.

回答2:

Not sure if this is what you want, but the example case can be implemented like:

@pytest.mark.parametrize(('param', 'expected'), [('param1', 5), ('param2', 10)]) def test_madeup(param, expected):     assert param == expected 

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