JAVA产生N个随机数和为S

 import java.math.BigDecimal; import java.util.ArrayList; import java.util.List;  public class NumUtils {      private static final BigDecimal TWO = new BigDecimal(2);      public static BigDecimal getNumsBelowNum(BigDecimal num){         return num.multiply(new BigDecimal(Math.random())).setScale(2,BigDecimal.ROUND_DOWN);     }       public static List<BigDecimal> find(int n , BigDecimal s){         List<BigDecimal> res = new ArrayList<>();         BigDecimal amounts = BigDecimal.ZERO;         for(int i = 0;i<n-1 ; i++){             BigDecimal amount = getNumsBelowNum((s.subtract(amounts)).divide(TWO).setScale(2,BigDecimal.ROUND_DOWN));             res.add(amount);             amounts = amounts.add(amount);         }         res.add(s.subtract(amounts).setScale(2,BigDecimal.ROUND_UP));  //这里得是round_up要不会有1分的问题         return res;     }   //测试一下     public static void main(String[] args) {         while (true){             List list = find(10,BigDecimal.valueOf(30)); //10个数字，和为30             System.out.println(list);             BigDecimal a = BigDecimal.ZERO;             for (int i = 0; i<list.size();i++){                 a = a.add((BigDecimal)list.get(i));             }             System.out.println(a);             if(a.compareTo(BigDecimal.valueOf(30))!=0){                 System.out.println("---------有异常数据拉！！");             }         }      }  }

适用于砍价，一次性把砍价的全部算出来，放List

30元，需要10个人砍，就是上面这样了

文章来源: https://blog.csdn.net/hanling911/article/details/92640162