问题
I have an array which I want to interpolate over the 1st axes. At the moment I am doing it like this example:
import numpy as np
from scipy.interpolate import interp1d
array = np.random.randint(0, 9, size=(100, 100, 100))
new_array = np.zeros((1000, 100, 100))
x = np.arange(0, 100, 1)
x_new = np.arange(0, 100, 0.1)
for i in x:
for j in x:
f = interp1d(x, array[:, i, j])
new_array[:, i, j] = f(xnew)
The data I use represents 10 years of 5-day averaged values for each latitude and longitude in a domain. I want to create an array of daily values.
I have also tried using splines. I don't really know how they work but it was not much faster.
Is there a way to do this without using for loops? If for loops must be used, are there other ways to speed this up?
Thank you in advance for any suggestions.
回答1:
You can specify an axis argument to interp1d:
import numpy as np
from scipy.interpolate import interp1d
array = np.random.randint(0, 9, size=(100, 100, 100))
x = np.linspace(0, 100, 100)
x_new = np.linspace(0, 100, 1000)
new_array = interp1d(x, array, axis=0)(x_new)
new_array.shape # -> (1000, 100, 100)
回答2:
Because you're interpolating regularly-gridded data, have a look at using scipy.ndimage.map_coordinates.
As a quick example:
import numpy as np
import scipy.ndimage as ndimage
interp_factor = 10
nx, ny, nz = 100, 100, 100
array = np.random.randint(0, 9, size=(nx, ny, nz))
# If you're not familiar with mgrid:
# http://docs.scipy.org/doc/numpy/reference/generated/numpy.mgrid.html
new_indicies = np.mgrid[0:nx:interp_factor*nx*1j, 0:ny, 0:nz]
# order=1 indicates bilinear interpolation. Default is 3 (cubic interpolation)
# We're also indicating the output array's dtype should be the same as the
# original array's. Otherwise, a new float array would be created.
interp_array = ndimage.map_coordinates(array, new_indicies,
order=1, output=array.dtype)
interp_array = interp_array.reshape((interp_factor * nx, ny, nz))
来源:https://stackoverflow.com/questions/7755871/interpolating-a-3d-array-in-python-how-to-avoid-for-loops