问题
How do i get all classes within a package?
回答1:
You can't. Classes can come in via many different class loaders, including remote ones.
回答2:
Here's a more complete way to solve this for jars, based on the idea posted by JG.
/**
* Scans all classloaders for the current thread for loaded jars, and then scans
* each jar for the package name in question, listing all classes directly under
* the package name in question. Assumes directory structure in jar file and class
* package naming follow java conventions (i.e. com.example.test.MyTest would be in
* /com/example/test/MyTest.class)
*/
public Collection<Class> getClassesForPackage(String packageName) throws Exception {
String packagePath = packageName.replace(".", "/");
ClassLoader classLoader = Thread.currentThread().getContextClassLoader();
Set<URL> jarUrls = new HashSet<URL>();
while (classLoader != null) {
if (classLoader instanceof URLClassLoader)
for (URL url : ((URLClassLoader) classLoader).getURLs())
if (url.getFile().endsWith(".jar") // may want better way to detect jar files
jarUrls.add(url);
classLoader = classLoader.getParent();
}
Set<Class> classes = new HashSet<Class>();
for (URL url : jarUrls) {
JarInputStream stream = new JarInputStream(url.openStream()); // may want better way to open url connections
JarEntry entry = stream.getNextJarEntry();
while (entry != null) {
String name = entry.getName();
int i = name.lastIndexOf("/");
if (i > 0 && name.endsWith(".class") && name.substring(0, i).equals(packagePath))
classes.add(Class.forName(name.substring(0, name.length() - 6).replace("/", ".")));
entry = stream.getNextJarEntry();
}
stream.close();
}
return classes;
}
回答3:
There's a snippet from here that does exactly what you want, assuming the classes can be found locally:
private static Class[] getClasses(String packageName)
throws ClassNotFoundException, IOException {
ClassLoader classLoader = Thread.currentThread().getContextClassLoader();
assert classLoader != null;
String path = packageName.replace('.', '/');
Enumeration<URL> resources = classLoader.getResources(path);
List<File> dirs = new ArrayList<File>();
while (resources.hasMoreElements()) {
URL resource = resources.nextElement();
dirs.add(new File(resource.getFile()));
}
ArrayList<Class> classes = new ArrayList<Class>();
for (File directory : dirs) {
classes.addAll(findClasses(directory, packageName));
}
return classes.toArray(new Class[classes.size()]);
}
private static List<Class> findClasses(File directory, String packageName) throws ClassNotFoundException {
List<Class> classes = new ArrayList<Class>();
if (!directory.exists()) {
return classes;
}
File[] files = directory.listFiles();
for (File file : files) {
if (file.isDirectory()) {
assert !file.getName().contains(".");
classes.addAll(findClasses(file, packageName + "." + file.getName()));
} else if (file.getName().endsWith(".class")) {
classes.add(Class.forName(packageName + '.' + file.getName().substring(0, file.getName().length() - 6)));
}
}
return classes;
}
回答4:
There is no global way to do that. That being said, if you know where your classes are coming from, you can walk the directory of a jar file or the file system.
回答5:
Java doesn't have discovery.
Most products that have the ability to add (discover) new classes either have a text file describing "Program Extensions" or a specific directory where you can place either classes or jars that uses a trick like @JG described. (This is what eclipse does and is recommended for any solution where the user may add the new module by hand)
回答6:
The above answers outline the required functionality. However, more details on the subject can be found here and here.
来源:https://stackoverflow.com/questions/1156552/java-package-introspection