INSERT into DB table with PDO prepare and bindParam

问题

In simple terms can someone explain what I am doing wrong here - I am simply trying to insert into a db with with prepare and bindParam, this is inserting 0 and Null into all the fields.

$sql = $db->prepare("INSERT INTO db_fruit VALUES (id=? ,type=? ,colour=?)");
$sql->bindParam(1, $newId);
$sql->bindParam(2, $type);
$sql->bindParam(3, $colour);
$sql->execute()

btw: this method has been working for me for UPDATE etc, but not in this case for INSERT

回答1:

Your syntax is incorrect, try this:

$sql = $db->prepare("INSERT INTO db_fruit (id, type, colour) VALUES (? ,? ,?)");
$sql->bindParam(1, $newId);
$sql->bindParam(2, $name);
$sql->bindParam(3, $colour);
$sql->execute();

回答2:

Expanding on A.O's answer, the following are also valid:

$sql = $db->prepare("INSERT INTO db_fruit (id, type, colour) VALUES (? ,? ,?)");
$sql->execute(array($newId, $name, $color));

And:

$sql = $db->prepare("INSERT INTO db_fruit (id, type, colour) VALUES (:id, :name, :color)");
$sql->execute(array('id' => $newId, 'name' => $name, 'color' => $color));

Might just be personal preference, but I find this syntax to be much cleaner.

回答3:

$sql = $db->prepare("INSERT INTO db_fruit (`id`, `type`, `colour`) VALUES (:id, :name, :colour)");
$sql->bindParam(':id', $newId, PDO::PARAM_INT);
$sql->bindParam(':type', $type, PDO::PARAM_INT);
$sql->bindParam(':colour', $colour, PDO::PARAM_STR);
$sql->execute();

来源：https://stackoverflow.com/questions/19599808/insert-into-db-table-with-pdo-prepare-and-bindparam