问题
In c++ you can do:
uint8 foo_bar
How would we do the same thing in ruby? Any alternatives?
This post seems close to it maybe someone can explain?
回答1:
Ruby abstracts away the internal storage of integers, so you don't have to worry about it.
If you assign an integer to a variable, Ruby will deal with the internals, allocating memory when needed. Smaller integers are of type Fixnum (stored in a single word), larger integers are of type Bignum.
a = 64
a.class #=> Fixnum; stored in a single word
a += 1234567890
a.class #=> Bignum; stored in more than a single word
Ruby is dynamically typed, so you cannot force a variable to contain only unsigned 8-bit integers (just as you cannot force a variable to only contain string values, etc.).
回答2:
You don't declare types in Ruby. The language is dynamically typed.
来源:https://stackoverflow.com/questions/1335710/how-to-declare-8-bit-unsigned-integer-in-ruby