type(list[0]) returns pynput.keyboard._win32.KeyCode

问题

My problem is how pynput returns the data (I hope that's how you would say it?).

So what I'm trying to do is have the listener record keyboard input, then use what letters are added to the list to make a string in word. Although, it seems like the letters aren't strings. Instead they return as pynput.keyboard._win32.KeyCode

Is there a way to convert that to a python readable string or something?
Like if: i typed f, t, w

print(type(list[0]), word)
return 'f', ftw

what it comes out as so far is

f[] pressed
t['f'] pressed
w['f', 't'] pressed
 ['f', 't', 'w'] pressed
['f', 't', 'w'] <class 'pynput.keyboard._win32.KeyCode'> # then basically nothing for word  
[] pressed

from pynput import keyboard


list = []
word = ''.join(list)


def press(key): 
    print(list, 'pressed') 
    if key is not keyboard.Key.space:
        list.append(key)
    elif keyboard.Key.space is key:
        pass
    elif keyboard.Key.enter is key:
        pass


def release(key):
    if key == keyboard.Key.space:
        print(type(list[0]), word)
        if word in hkey:
            func()
        list.clear()

with keyboard.Listener(on_press=press, on_release=release) as listener:
    listener.join()

回答1:

You can extract the character from the pressed key by using the char attribute of the pynput.keyboard._win32.KeyCode. In other words, in your press function, you would append key.char to the list. Also, I would avoid using list as a variable name.

def press(key):
    print(_list, 'pressed')
    if key is not keyboard.Key.space:
        _list.append(key.char)         # <-- Note: key.char
    elif keyboard.Key.space is key:
        pass
elif keyboard.Key.enter is key:
    pass

来源：https://stackoverflow.com/questions/52241868/typelist0-returns-pynput-keyboard-win32-keycode

标签

python

listener

event-listener

pynput