return multiple json results

问题

I have to output $var1. To do that, I return results by using

sendJson($var1);

And this is working fine for me. Now I want to pass two variables $var1 and $var2 using sendJson();. Is it possible?

回答1:

Put them all inside an array:

sendJson(array($var1, $var2));

Or name them if you don't want to do it index-based:

sendJson(array('var1' => $var1, 'var2' => $var2))

回答2:

name your array keys:

echo json_encode( array (
    'messages' => array(
        'peter' => 'Hello',
        'john'  => 'Hi to you too'
    ),
    'users'     => array (
        'peter', 'john'
    )
));

and then access them like this:

resp.messages.peter
resp.messages.john

or

resp.users[0], resp.users[1].... etc.

来源：https://stackoverflow.com/questions/13910024/return-multiple-json-results