问题
I have base class Foo with method spam and class Bar which overrides spam. I need to call spam of base class in method of some callback object which is defined in-place:
public class Foo {
    public void spam() {
        // ...
    }
}
public class Bar extends Foo {
    @Override
    public void spam() {
        objectWhichRequireCallback(new Callback {
            @Override
            public void onCallback() {
                super.spam();
            }
        });
    }
}
This code is not working because super is related to Callback, not Bar class. Is it possible to call super method from object defined in-place?
回答1:
public class Bar extends Foo {
    @Override
    public void spam() {
        objectWhichRequireCallback(new Callback {
            @Override
            public void onCallback() {
                Bar.super.spam();
            }
        });
    }
}
EDIT : Sorry. DIdn't realize the method names are the same.
回答2:
You can create a wrapper function for this, in Bar
public class Bar...
    public void mySuperSpam(){
        super.spam();
    }
回答3:
Try this: Bar.super.spam();
Bar.this.spam(); is compiled but it will cause infinite recursion because you call the same spam() itself.
来源:https://stackoverflow.com/questions/7079600/java-how-to-call-super-method-from-inner-in-place-class