Why 'int' by default, but not 'byte'? [duplicate]

问题

This question already has answers here:

How do you specify a byte literal in Java? (6 answers)

Closed 9 months ago.

Explain me please, why, when I write 4 overloaded methods and call it => it chooses method with 'int' as default, but not 'byte', which is closer/better, because it can storage values from -127 to 128?

class Main {
    public static void method(short s) {
        System.out.println("short");
    }

    public static void method(byte b) {
        System.out.println("byte");
    }

    public static void method(int i) {
        System.out.println("int");
    }

    public static void method(long l) {
        System.out.println("long");
    }

    public static void main(String[] args) {
        // put your code here
        method(10);
    }
}

回答1:

Because the Java Language Specification says so.

Section 3.10.1. Integer Literals says:

An integer literal is of type long if it is suffixed with an ASCII letter L or l (ell); otherwise it is of type int (§4.2.1).

So your numeric literal 10 is of type int.

回答2:

It's because default type of number's literal is integer. To specify long literal you should add L at the end. To specify byte literal - you should cast the value

来源：https://stackoverflow.com/questions/61467032/why-int-by-default-but-not-byte