while loop result at table, sends first row when submit form in php

北城余情 提交于 2021-01-28 10:06:48

问题


1.fetch user data and display in tabular fashion

                  <?php
                      while($row=mysqli_fetch_assoc($rResultSet))
                     {
                   ?>

                  <td><?php echo $row['id']?></td>
                  <td><?php echo $row['name']?></td>
                  <td><?php echo $row['user_role']?></td>
                  <td><?php echo $row['start_date']?></td>
                  <td>

                  <form id='euser' action='edituser.php' method='post'>
                  <input type="hidden" name="id" value="<?php echo $row['id']?>">
                  <input type="hidden" name="type" value="edituser">

                  <a  href="javascript: document.getElementById('euser').submit();">Edit</i></a>|
                 </form>
                 <?php 
                 }
                 ?>

result of this code

2.when click on Edit link every time first id which 16 throw by form

i need , when press link edit at id 17 then id 17 thrown by form


回答1:


Try below if it help :

<?php
    while($row=mysqli_fetch_assoc($rResultSet))
{
?>
<tr>
<td><?php echo $row['id'];?></td>
<td><?php echo $row['name'];?></td>
<td><?php echo $row['user_role'];?></td>
<td><?php echo $row['start_date'];?></td>
<td>

    <form id='<?php echo $row['id'];?>' action='edituser.php' method='post'>
        <input type="hidden" name="id" value="<?php echo $row['id'];?>">
        <input type="hidden" name="type" value="edituser">

        <a  href="javascript: document.getElementById('<?php echo $row['id'];?>').submit();">Edit</a>|
    </form>
</td>
</tr>
 <?php 
   }
 ?>



回答2:


The problem is because of form's id attribute, it has to be unique for each row. Right now you're assigning the same id value euser for each row. For maintaining the uniqueness of id value, what you can do is, append the $row['id'] with euser for each table row. Also, you forgot to encapsulate each table row in <tr>...</tr>. So your code should be like this:

<?php
    while($row=mysqli_fetch_assoc($rResultSet)){
    ?>
        <tr>
            <td><?php echo $row['id']?></td>
            <td><?php echo $row['name']?></td>
            <td><?php echo $row['user_role']?></td>
            <td><?php echo $row['start_date']?></td>
            <td>

            <form id='euser<?php echo $row['id']?>' action='edituser.php' method='post'>
                <input type="hidden" name="id" value="<?php echo $row['id']?>">
                <input type="hidden" name="type" value="edituser">

                <a  href="javascript: document.getElementById('euser<?php echo $row['id']?>').submit();">Edit</i></a>|
            </form>
        <tr>
    <?php 
    }
?>


来源:https://stackoverflow.com/questions/44983764/while-loop-result-at-table-sends-first-row-when-submit-form-in-php

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