问题
I Just want to make sure I am reading this right:
movl 12(%ebp), %edx
leal (%edx, %edx, 4), %eax
I read the first line as: edx = [epb + 12], and the second line as: eax = edx + edx*4
Can anybody clarify?
Also, what if I had the following two lines:
leal (%edx, %edx, 4), %eax
leal (%edx, %edx, 2), %eax
Once the second line is executed, would the eax register be overwritten?
And the eax = edx + edx*4 is multiplying the address by 4? Or the contents of the address by 4?
回答1:
You're right. The LEA instruction is used to Load (the) Effective Address, and can be used for address arithmetic and sometimes also ordinary arithmetic, if you don't need the flags.
回答2:
The instruction movl 12(%ebp), %edx means: edx = [ebp + 12]. This is a memory reference (a read operation) to the address ebp + 12 whose contents (a double word) are read to edx register.
The instruction leal (%edx, %edx, 4), %eax means: eax = edx * 5 (which is a simplification of eax = edx + edx * 4). The leal instruction doesn't do memory references. It only performs arithmetic with registers.
As an answer to your second question: Yes, eax would be overwritten because the instruction leal (%edx, %edx, 2), %eax means eax = edx * 3 which is different from the first instruction, eax = edx * 5.
来源：https://stackoverflow.com/questions/9153282/lea-assembly-instruction