Case insensitive search in Mongo

Question

I am using a case insensitive search in Mongo, something similar to https://stackoverflow.com/q/5500823/1028488.

ie I am using a regex with options i. But I am am having trouble restricting the regex to just that word, its performs more like a 'Like' in SQL

eg: if I use query like {"SearchWord" : { '$regex' : 'win', $options: '-i' }}, it shows me results for win, window & winter. How do i restrict it to jsut show win?

I tried /^win$/ but its sayin invalid Json.... Please suggest a way.

Thanks in advance

Answer 1

You can use '$regex':'^win$' or /^win$/i (notice no quote on the second one)

Source here : Regex in queries with Mongo

Answer 2

You can Use $options => i for case insensitive search. Giving some possible examples required for string match.

Exact case insensitive string

db.collection.find({name:{'$regex' : '^string$', '$options' : 'i'}})

Contains string

db.collection.find({name:{'$regex' : 'string', '$options' : 'i'}})

Start with string

db.collection.find({name:{'$regex' : '^string', '$options' : 'i'}})

End with string

db.collection.find({name:{'$regex' : 'string$', '$options' : 'i'}})

Doesn't Contains string

db.collection.find({name:{'$regex' : '^((?!string).)*$', '$options' : 'i'}})

Keep this as a bookmark, and a reference for any other alterations you may need. http://www.cheatography.com/davechild/cheat-sheets/regular-expressions/

Answer 3

UPDATE: As of MongoDB 2.4 one would use a "text" index and full text search query to do this. You can read about them here. If using a recent MongoDB the approach below would be silly and unecessary.

However, if you have MongoDB < 2.4.0 you could use a regular expression like so:

> db.reg.insert({searchword: "win"})
> db.reg.insert({searchword: "window"})
> db.reg.insert({searchword: "Win"})

> db.reg.find()
{ "_id" : ObjectId("4ecd2e33dd68c9021e453d12"), "searchword" : "win" }
{ "_id" : ObjectId("4ecd2e36dd68c9021e453d13"), "searchword" : "window" }
{ "_id" : ObjectId("4ecd2e39dd68c9021e453d14"), "searchword" : "Win" }

> db.reg.find({ searchword: /^win$/i })
{ "_id" : ObjectId("4ecd2e33dd68c9021e453d12"), "searchword" : "win" }
{ "_id" : ObjectId("4ecd2e39dd68c9021e453d14"), "searchword" : "Win" }

However, your version wasn't working because you don't need the "/"s when using the $regex operator:

> db.reg.find({ searchword: { $regex: "^win$", $options: '-i' }})
{ "_id" : ObjectId("4ecd2e33dd68c9021e453d12"), "searchword" : "win" }
{ "_id" : ObjectId("4ecd2e39dd68c9021e453d14"), "searchword" : "Win" }

Please note that case insensitive queries do not use the index so it might make sense to make a lowercase searchword field so that you can speed that query up.

Go here for more info on RegularExpressions

Answer 4

Use $strcasecmp. The aggregation framework was introduced in MongoDB 2.2. You can use the string operator "$strcasecmp" to make a case-insensitive comparison between strings. It's more recommended and easier than using regex.

Here's the official document on the aggregation command operator: https://docs.mongodb.com/manual/reference/operator/aggregation/strcasecmp/#exp._S_strcasecmp .

Answer 5

For Case insensitive db.users.find({"name":{ $regex : new RegExp("Vi", "i") }})

For Case sensitive db.users.find({"name":"Vi"}) or db.users.find({"email":"example@mail.com"})

search in user table

name is column name and "Vi" text that are searched