Python open() flags for open or create

问题

What is the mode for open(..., mode) in Python 3 that opens a file that

• create if does not exist
• do NOT truncate
• binary mode

I tested r+b but that fails on missing file, w+b truncates it, and a+b seem to turn all writes into appends, while I need to overwrite some data.

回答1:

A workaround is to catch the exception and open with another mode. I would still accept a better solution.

try:
    self.file = open(filename, "r+b")
except FileNotFoundError:
    self.file = open(filename, "w+b")

回答2:

This is a massive deficiency in C & Python. There's no way to do this via open()!!

Python's open() is like the fopen() API in C, and neither has this ability.

Note that the try/except approach you posted has a race condition:
The file can be created in between the two calls, and suddenly you'll truncate it with the second call.

However: you can achieve what you want using os.open() and os.fdopen():

fd = os.open(path, os.O_CREAT | os.O_RDWR | os.O_BINARY)
if fd != -1:
    f = os.fdopen(fd, 'r+b')  # Now use 'f' normally; it'll close `fd` itself

来源：https://stackoverflow.com/questions/38530910/python-open-flags-for-open-or-create