Leetcode 108. Convert Sorted Array to Binary Search Tree

 

 

顺序数组建树，要从中间开始建树。

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    TreeNode* sortedArrayToBST(vector<int>& nums) {
        return buildTree(nums, 0, nums.size() - 1);
    }
    TreeNode* buildTree(vector<int>& nums, int l, int r){
        if(l > r) return NULL;
        int m = l + ((r - l) >> 1);
        TreeNode *t = new TreeNode(nums[m]);
        t->left = buildTree(nums, l, m - 1);
        t->right = buildTree(nums, m + 1, r);
        return t;
    }
};

 

来源：https://www.cnblogs.com/littlepage/p/12271803.html