python的多个装饰器实现信息的登录

要求

['root','admin','redhat']
1.user in [ ]
2.user+vip

编程

import functools
import inspect
login_session = ['root','admin','redhat']
def is_login(fun):
    @functools.wraps(fun)
    def warapper(*args,**kwargs):#('root',)
        if args[0] in login_session:
            temp = fun(*args,**kwargs)
            return temp
        else:
            print('Error:%s 没哟登陆成功' %(args[0]))
    return warapper

def is_admin(fun):
    @functools.wraps(fun)
    # """
    #  inspect.getcallargs会返回一个字典
    #  key:形参
    #  value:对应的实参
    # """
    def wrapper(*args,**kwargs):
        inspect_res = inspect.getcallargs(fun,*args,**kwargs)
        print('inspect的返回值是:%s' %(inspect_res))
        if inspect_res.get('name') == 'root':
            temp = fun(*args,**kwargs)
            return temp
        else:
            print('not root user,no permisson add user')
    return wrapper


@is_login
@is_admin
def add_user(name): # is_login((is_admin(adduser)) is_login(wrapper())
    print('add_user')

add_user('python')

结果

来源：CSDN

作者：一坨小红花

链接：https://blog.csdn.net/qq_45652989/article/details/103951612