问题
#include <stdio.h>
/* global variable declaration */
int g = 20;
int main ()
{
/* local variable declaration */
int g = 10;
printf ("value of g = %d %d\n", g,::g);
return 0;
}
When i am trying to run this program. It is throwing error main.c:11:39: error: expected expression before ':' token
printf ("value of g = %d %d\n", g,::g);. But if it is written in C++, it works fine.
回答1:
No, that's a C++ feature. In C, declaring a variable in an inner scope will hide the one in the outer scope.
If you must do it, you can use pointers to get at the outer scope but it's a bit of a kludge and not something I'd recommend:
#include <stdio.h>
int g = 20;
int main () {
int *pGlobalG = &g;
int g = 10;
printf ("value of g = %d %d\n", g, *pGlobalG);
return 0;
}
来源：https://stackoverflow.com/questions/21201788/does-c-supports-scope-resolution