问题
This question is related to the post here. Is it possible to initialize an array in a function call or constructor call? For example, class foo's constructor wants an array of size 3, so I want to call foo( { 0, 0, 0 } ). I've tried this, and it does not work. I'd like to be able to initialize objects of type foo in other objects' constructor initialization lists, or initialize foo's without first creating a separate array. Is this possible?
回答1:
Not in the current standard. It will be possible in C++11
In gcc you can use a cast to force the creation of a temporal, but it is not standard c++ (C99):
typedef int array[2];
void foo( array ) {} // Note: the actual signature is: void foo( int * )
int main() {
foo( (array){ 1, 2 } );
}
回答2:
If permitted by your design, you can consider wrapping the data inside a class and in default constructor initialize with 0 (or any value of your choice)
来源：https://stackoverflow.com/questions/2676697/c-array-initialization-in-function-call-or-constructor-call