HoughLines transform in opencv

问题

I am working on image processing using opencv and Eclipse.

  vector<Vec2f> lines;  
  HoughLines(dst, lines, 1, CV_PI/180, 100, 0, 0 );

  for( size_t i = 0; i < lines.size(); i++ )  
  {  
     float rho = lines[i][0], theta = lines[i][1];  
     Point pt1, pt2;  
     double a = cos(theta), b = sin(theta);  
     double x0 = a*rho, y0 = b*rho;  
     pt1.x = cvRound(x0 + 1000*(-b));  
     pt1.y = cvRound(y0 + 1000*(a));  
     pt2.x = cvRound(x0 - 1000*(-b));  
     pt2.y = cvRound(y0 - 1000*(a));  
     line( cdst, pt1, pt2, Scalar(0,0,255), 3, CV_AA);  
  }  

Can anyone explain that how the points are being defined by this code. We are using

y=(-cos(theta)/sin(theta))x + r/(sin(theta))
rho=xo*cos(theta) + yo*sin(theta)

I am not able to understand why the multiplication of 1000 is being done in the line

pt1.x = cvRound(x0 + 1000*(-b));  

please try to explain this in simple terms. Thanks in advance

回答1:

The question has already been answered. But since I spend the last fifteen minutes drawing this diagram I might as well post it anyway. Maybe it helps:

So what you have is a Point p0 = (x0,y0) which is on the line. You then compute two other points on the line which are 1000 units away from p0 in each direction.

回答2:

Here's a detailed explanation for this piece of code:

 pt1.x = cvRound(x0 + 1000*(-b));  
 pt1.y = cvRound(y0 + 1000*(a));  
 pt2.x = cvRound(x0 - 1000*(-b));  
 pt2.y = cvRound(y0 - 1000*(a));

(click on the picture to see it in full size)

In this case d1 = d2 = 1000.

回答3:

The code appears to be trying to draw a line from the parameters returned by the Hough Transform function. The multiplication by 1000 makes it so that your points are moved along the line (in opposite directions, which is why pt1 adds and pt2 subtracts) from the starting position in order to actually draw the line. Different values of that number should give you different line segment lengths. If you are curious, try replacing the value with a variable (like line_length) and then vary the value of that variable to see how it affects the appearance of your output.

来源：https://stackoverflow.com/questions/18782873/houghlines-transform-in-opencv