MongoDB - Aggregation - To get unique items in array

问题

Here's my MongoDB collection:

{
    "_id" : ObjectId("515d8f53175b8ecb053425c2"),
    "category" : "Batteries",
    "products" : [
        {
            "brand" : "Duracell",
            "item" : [
                "AA",
                "AAA"
            ]
        },
        {
            "brand" : "Everyday",
            "item" : [
                "9V",
                "AA",
                "12V"
            ]
        }
    ]
}

The output that I need is

1) Unique list of all items

{["AA", "AAA", "9V", "12V"]}

and 2. unique list of items per product

{
    "category" : "Batteries",
    "item": ["AA", "AAA", "9V", "12V"]
}

I'm very new to MongoDB, and I tried different aggregations functions and nothing seems to work. Please help.

回答1:

After few more tries, I had solved this. Here's the commands:

db.xyz.aggregate( {$project: {a: '$products.item'}}, 
    {$unwind: '$a'}, 
    {$unwind: '$a'}, 
    {$group: {_id: 'a', items: {$addToSet: '$a'}}});

and

db.xyz.aggregate( {$project: {category: 1, a: '$products.item'}}, 
    {$unwind: '$a'}, 
    {$unwind: '$a'}, 
    {$group: {_id: '$category', items: {$addToSet: '$a'}}});

回答2:

I am not sure what you all you have tried in the aggregation function but i thought unwind will help you to do the same , assuming you are not able to get it done , we have a map-reduce which will allow you to easily do this one . You can look into the http://docs.mongodb.org/manual/applications/map-reduce/ . It allow you to get the data in a manner you want and you can easily get the list . I think $unwind on the tags column and then $group them will always give the us the list of distinct tags as required by you in 1 and for 2nd case create $group on two key category and item which was $unwind earlier.

来源：https://stackoverflow.com/questions/15814526/mongodb-aggregation-to-get-unique-items-in-array

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mongodb

mongodb-php

mongodb-query