问题
Here is the example,
>>> x = ["a","b","c"]
>>> yy = [x] * 3
>>> yy
[['a', 'b', 'c'], ['a', 'b', 'c'], ['a', 'b', 'c']]
>>> yy[0][0] = 'A'
>>> yy
[['A', 'b', 'c'], ['A', 'b', 'c'], ['A', 'b', 'c']]
>>>
When i do yy[0][0] = 'A', it replaced to all the first element of the sub-list. What i got from here is when i do [x] * 3, it creates some reference to list x but not sure how really it works. Could some one please explain.
Thanks in advanced. James
回答1:
[x]*3 creates 3 references to the same list. You have to create three different lists:
>>> yy = [list('abc') for _ in range(3)]
>>> yy[0][0]='A'
>>> yy
[['A', 'b', 'c'], ['a', 'b', 'c'], ['a', 'b', 'c']]
The first line creates a new list using a list comprehension that loops 3 times.
Using id(), you can visualize that the same list reference is duplicated:
>>> x=list('abc')
>>> id(x)
67297928 # list object id
>>> yy=[x]*3 # create a list with x, duplicated...
>>> [id(i) for i in yy]
[67297928, 67297928, 67297928] # same id multipled
>>> yy = [list('abc') for _ in range(3)]
>>> [id(i) for i in yy]
[67298248, 67298312, 67297864] # three different ids
来源：https://stackoverflow.com/questions/19886645/regarding-python-list-with-reference