Hide button on one touch itself

问题

i want to hide button on one touch itself. when the user touches the button that button should get hide but on one touch.The buttons are moving randomly. The moving buttons shoul get hide on touch. i have done it but after two three times pressing only it gets hide. i am using touchupinside event. Can anyone help me?

-(IBAction)clickButton1:(id)sender
{
    if (button1.tag==1)
    {
        button1.hidden=TRUE;
    }
    else
    {
        button1.hidden=FALSE;
    }
}
-(IBAction)clickButton2:(id)sender
{
    if(button1.hidden==TRUE && button3.hidden==FALSE) 
    {
        button2.hidden=TRUE;
    }
    else
    {
        button2.hidden=FALSE;
    }
}

Thanks in advance

回答1:

Replace your code with this Button touchUpInside

-(IBAction)hide:(id)sender
{
    UIButton *tmp = (UIButton *)sender;
    tmp.hidden = YES;
}

回答2:

Replace your first IBAction method with this one:

 -(IBAction)clickButton1:(id)sender
{
  UIButton *button1 = (UIButton *)sender;
  if (button1.tag==1)
 {
   button1.hidden=TRUE;
 }
 else
 {
   button1.hidden=FALSE;
 }
}

回答3:

You can create your button on viewDidLoad with loop

-(void) viewDidLoad{
     for ( c = 0; c < 10; c++ ){
           Buttons[c] = [[UIButton alloc] init];
           Buttons[c].tag = c;
      }
}

after that you can control the show hide with following code.

-(IBAction)yourActionMethod:(id)sender
{
    //your normal action codes here
    UIButton *tmp = (UIButton *)sender;
    if (tmp.tag == 0) {
          // some codes
    } else {....}

    //control buttons of the 

    for (int i = 0; i < tmp.tag; i++){
          Buttons[i].hidden = yes;
    }
    
}

来源：https://stackoverflow.com/questions/10101253/hide-button-on-one-touch-itself