bash - Shell script opening multiple terminals and executing distinct commands [closed]

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Closed 5 years ago.

I've tried to write my own shell script. So far I've managed to open 4 xterminals that can only execute ONE command because of the 'hold' option.

If i don't use this option, the terminals just disappear.

Here is my code :

#!/bin/sh
xterm -title "App 1" -hold -e mycommand | mysecondcommand  &
xterm -title "App 2" -hold -e mycommand | mysecondcommand  &
xterm -title "App 3" -hold -e mycommand | mysecondcommand  &
xterm -title "App 4" -hold -e mycommand | mysecondcommand

Not so sure if I'm supposed to execute the second command in the same terminal that way.

Any ideas ?

Thank you

回答1:

Without -hold, the xterm will close as soon as the command is completed. You can execute multiple commands by using double quotes and command separators (eg ;, &):

xterm -title "App 1" -e "mycommand; mysecondcommand" 

来源：https://stackoverflow.com/questions/22656359/bash-shell-script-opening-multiple-terminals-and-executing-distinct-commands