Bash: How to print the filename of the nth file in a folder

问题

I'm getting a parsing error in the 773rd file of a folder. Is it possible to print the name of the file in bash?

I've tried using this to print it but it returns a blank.

files=(/path/to/files)
echo "${files[773]}"

回答1:

Very close, but you need to actually do a glob to collect the list into your array, rather than having a list with only one element (the parent directory):

files=( /path/to/files/* )
echo "${files[772]}"

If you want to represent your filename in a way that represents nonprintable characters in a human-readable way, echo is the wrong tool. Instead, consider:

printf '%q\n' "${files[772]}"

If your path is coming from a variable, be sure to quote its expansion, but not the glob character:

files=( "$dir"/* )

来源：https://stackoverflow.com/questions/25631016/bash-how-to-print-the-filename-of-the-nth-file-in-a-folder