问题
I know that I can use Fixnum#to_s to represent integers as strings in binary format. However 1.to_s(2) produces 1 and I want it to produce 00000001. How can I make all the returned strings have zeros as a fill up to the 8 character? I could use something like:
binary = "#{'0' * (8 - (1.to_s(2)).size)}#{1.to_s(2)}" if (1.to_s(2)).size < 8
but that doesn't seem very elegant.
回答1:
Use string format.
"%08b" % 1
# => "00000001"
回答2:
Using String#rjust:
1.to_s(2).rjust(8, '0')
=> "00000001"
回答3:
Use the String#% method to format a string
"%08d" % 1.to_s(2)
# => "00000001"
Here is a reference for different formatting options.
来源:https://stackoverflow.com/questions/19853566/how-to-return-a-fixed-length-binary-representation-of-an-integer-in-ruby