问题
I have a table transaction which has duplicates. i want to keep the record that had minimum id and delete all the duplicates based on four fields DATE, AMOUNT, REFNUMBER, PARENTFOLDERID. I wrote this query but i am not sure if this can be written in an efficient way. Do you think there is a better way? I am asking because i am worried about the run time.
DELETE FROM TRANSACTION
WHERE ID IN
(SELECT FIT2.ID
FROM
(SELECT MIN(ID) AS ID, FIT.DATE, FIT.AMOUNT, FIT.REFNUMBER, FIT.PARENTFOLDERID
FROM EWORK.TRANSACTION FIT
GROUP BY FIT.DATE, FIT.AMOUNT , FIT.REFNUMBER, FIT.PARENTFOLDERID
HAVING COUNT(1)>1 and FIT.AMOUNT >0) FIT1,
EWORK.TRANSACTION FIT2
WHERE FIT1.DATE=FIT2.DATE AND
FIT1.AMOUNT=FIT2.AMOUNT AND
FIT1.REFNUMBER=FIT2.REFNUMBER AND
FIT1.PARENTFOLDERID=FIT2.PARENTFOLDERID AND
FIT1.ID<>FIT2.ID)
回答1:
It would probably be more efficient to do something like
DELETE FROM transaction t1
WHERE EXISTS( SELECT 1
FROM transaction t2
WHERE t1.date = t2.date
AND t1.refnumber = t2.refnumber
AND t1.parentFolderId = t2.parentFolderId
AND t2.id > t1.id )
回答2:
DELETE FROM transaction
WHERE ID IN (
SELECT ID
FROM (SELECT ID,
ROW_NUMBER () OVER (PARTITION BY date
,amount
,refnumber
,parentfolderid
ORDER BY ID) rn
FROM transaction)
WHERE rn <> 1);
I will try like this
回答3:
I would try something like this:
DELETE transaction
FROM transaction
LEFT OUTER JOIN
(
SELECT MIN(id) as id, date, amount, refnumber, parentfolderid
FROM transaction
GROUP BY date, amount, refnumber, parentfolderid
) as validRows
ON transaction.id = validRows.id
WHERE validRows.id IS NULL
来源:https://stackoverflow.com/questions/10017027/sql-to-delete-the-duplicates-in-a-table