问题
Consider the following:
PImpl.hpp
class Impl;
class PImpl
{
Impl* pimpl;
PImpl() : pimpl(new Impl) { }
~PImpl() { delete pimpl; }
void DoSomething();
};
PImpl.cpp
#include "PImpl.hpp"
#include "Impl.hpp"
void PImpl::DoSomething() { pimpl->DoSomething(); }
Impl.hpp
class Impl
{
int data;
public:
void DoSomething() {}
}
client.cpp
#include "Pimpl.hpp"
int main()
{
PImpl unitUnderTest;
unitUnderTest.DoSomething();
}
The idea behind this pattern is that Impl's interface can change, yet clients do not have to be recompiled. Yet, I fail to see how this can truly be the case. Let's say I wanted to add a method to this class -- clients would still have to recompile.
Basically, the only kinds of changes like this that I can see ever needing to change the header file for a class for are things for which the interface of the class changes. And when that happens, pimpl or no pimpl, clients have to recompile.
What kinds of editing here give us benefits in terms of not recompiling client code?
回答1:
The main advantage is that the clients of the interface aren't forced to include the headers for all your class's internal dependencies. So any changes to those headers don't cascade into a recompile of most of your project. Plus general idealism about implementation-hiding.
Also, you wouldn't necessarily put your impl class in its own header. Just make it a struct inside the single cpp and make your outer class reference its data members directly.
Edit: Example
SomeClass.h
struct SomeClassImpl;
class SomeClass {
SomeClassImpl * pImpl;
public:
SomeClass();
~SomeClass();
int DoSomething();
};
SomeClass.cpp
#include "SomeClass.h"
#include "OtherClass.h"
#include <vector>
struct SomeClassImpl {
int foo;
std::vector<OtherClass> otherClassVec; //users of SomeClass don't need to know anything about OtherClass, or include its header.
};
SomeClass::SomeClass() { pImpl = new SomeClassImpl; }
SomeClass::~SomeClass() { delete pImpl; }
int SomeClass::DoSomething() {
pImpl->otherClassVec.push_back(0);
return pImpl->otherClassVec.size();
}
回答2:
There has been a number of answers... but no correct implementation so far. I am somewhat saddened that examples are incorrect since people are likely to use them...
The "Pimpl" idiom is short for "Pointer to Implementation" and is also referred to as "Compilation Firewall". And now, let's dive in.
1. When is an include necessary ?
When you use a class, you need its full definition only if:
- you need its size (attribute of your class)
- you need to access one of its method
If you only reference it or have a pointer to it, then since the size of a reference or pointer does not depend on the type referenced / pointed to you need only declare the identifier (forward declaration).
Example:
#include "a.h"
#include "b.h"
#include "c.h"
#include "d.h"
#include "e.h"
#include "f.h"
struct Foo
{
Foo();
A a;
B* b;
C& c;
static D d;
friend class E;
void bar(F f);
};
In the above example, which includes are "convenience" includes and could be removed without affecting the correctness ? Most surprisingly: all but "a.h".
2. Implementing Pimpl
Therefore, the idea of Pimpl is to use a pointer to the implementation class, so as not to need to include any header:
- thus isolating the client from the dependencies
- thus preventing compilation ripple effect
An additional benefit: the ABI of the library is preserved.
For ease of use, the Pimpl idiom can be used with a "smart pointer" management style:
// From Ben Voigt's remark
// information at:
// http://en.wikibooks.org/wiki/More_C%2B%2B_Idioms/Checked_delete
template<class T>
inline void checked_delete(T * x)
{
typedef char type_must_be_complete[ sizeof(T)? 1: -1 ];
(void) sizeof(type_must_be_complete);
delete x;
}
template <typename T>
class pimpl
{
public:
pimpl(): m(new T()) {}
pimpl(T* t): m(t) { assert(t && "Null Pointer Unauthorized"); }
pimpl(pimpl const& rhs): m(new T(*rhs.m)) {}
pimpl& operator=(pimpl const& rhs)
{
std::auto_ptr<T> tmp(new T(*rhs.m)); // copy may throw: Strong Guarantee
checked_delete(m);
m = tmp.release();
return *this;
}
~pimpl() { checked_delete(m); }
void swap(pimpl& rhs) { std::swap(m, rhs.m); }
T* operator->() { return m; }
T const* operator->() const { return m; }
T& operator*() { return *m; }
T const& operator*() const { return *m; }
T* get() { return m; }
T const* get() const { return m; }
private:
T* m;
};
template <typename T> class pimpl<T*> {};
template <typename T> class pimpl<T&> {};
template <typename T>
void swap(pimpl<T>& lhs, pimpl<T>& rhs) { lhs.swap(rhs); }
What does it have that the others didn't ?
- It simply obeys the Rule of Three: defining the Copy Constructor, Copy Assignment Operator and Destructor.
- It does so implementing the Strong Guarantee: if the copy throws during an assignment, then the object is left unchanged. Note that the destructor of
Tshould not throw... but then, that is a very common requirement ;)
Building on this, we can now define Pimpl'ed classes somewhat easily:
class Foo
{
public:
private:
struct Impl;
pimpl<Impl> mImpl;
}; // class Foo
Note: the compiler cannot generate a correct constructor, copy assignment operator or destructor here, because doing so would require access to Impl definition. Therefore, despite the pimpl helper, you will need to define manually those 4. However, thanks to the pimpl helper the compilation will fail, instead of dragging you into the land of undefined behavior.
3. Going Further
It should be noted that the presence of virtual functions is often seen as an implementation detail, one of the advantages of Pimpl is that we have the correct framework in place to leverage the power of the Strategy Pattern.
Doing so requires that the "copy" of pimpl be changed:
// pimpl.h
template <typename T>
pimpl<T>::pimpl(pimpl<T> const& rhs): m(rhs.m->clone()) {}
template <typename T>
pimpl<T>& pimpl<T>::operator=(pimpl<T> const& rhs)
{
std::auto_ptr<T> tmp(rhs.m->clone()); // copy may throw: Strong Guarantee
checked_delete(m);
m = tmp.release();
return *this;
}
And then we can define our Foo like so
// foo.h
#include "pimpl.h"
namespace detail { class FooBase; }
class Foo
{
public:
enum Mode {
Easy,
Normal,
Hard,
God
};
Foo(Mode mode);
// Others
private:
pimpl<detail::FooBase> mImpl;
};
// Foo.cpp
#include "foo.h"
#include "detail/fooEasy.h"
#include "detail/fooNormal.h"
#include "detail/fooHard.h"
#include "detail/fooGod.h"
Foo::Foo(Mode m): mImpl(FooFactory::Get(m)) {}
Note that the ABI of Foo is completely unconcerned by the various changes that may occur:
- there is no virtual method in
Foo - the size of
mImplis that of a simple pointer, whatever what it points to
Therefore your client need not worry about a particular patch that would add either a method or an attribute and you need not worry about the memory layout etc... it just naturally works.
回答3:
With the PIMPL idiom, if the internal implementation details of the IMPL class changes, the clients do not have to be rebuilt. Any change in the interface of the IMPL (and hence header file) class obviously would require the PIMPL class to change.
BTW, In the code shown, there is a strong coupling between IMPL and PIMPL. So any change in class implementation of IMPL also would cause a need to rebuild.
回答4:
Consider something more realistic and the benefits become more notable. Most of the time that I have used this for compiler firewalling and implementation hiding, I define the implementation class within the same compilation unit that visible class is in. In your example, I wouldn't have Impl.h or Impl.cpp and Pimpl.cpp would look something like:
#include <iostream>
#include <boost/thread.hpp>
class Impl {
public:
Impl(): data(0) {}
void setData(int d) {
boost::lock_guard l(lock);
data = d;
}
int getData() {
boost::lock_guard l(lock);
return data;
}
void doSomething() {
int d = getData();
std::cout << getData() << std::endl;
}
private:
int data;
boost::mutex lock;
};
Pimpl::Pimpl(): pimpl(new Impl) {
}
void Pimpl::doSomething() {
pimpl->doSomething();
}
Now no one needs to know about our dependency on boost. This gets more powerful when mixed together with policies. Details like threading policies (e.g., single vs multi) can be hidden by using variant implementations of Impl behind the scenes. Also notice that there are a number of additional methods available in Impl that aren't exposed. This also makes this technique good for layering your implementation.
回答5:
In your example, you can change the implementation of data without having to recompile the clients. This would not be the case without the PImpl intermediary. Likewise, you could change the signature or name of Imlp::DoSomething (to a point), and the clients wouldn't have to know.
In general, anything that can be declared private (the default) or protected in Impl can be changed without recompiling the clients.
回答6:
In non-Pimpl class headers the .hpp file defines the public and private components of your class all in one big bucket.
Privates are closely coupled to your implementation, so this means your .hpp file really can give away a lot about your internal implementation.
Consider something like the threading library you choose to use privately inside the class. Without using Pimpl, the threading classes and types might be encountered as private members or parameters on private methods. Ok, a thread library might be a bad example but you get the idea: The private parts of your class definition should be hidden away from those who include your header.
That's where Pimpl comes in. Since the public class header no longer defines the "private parts" but instead has a Pointer to Implementation, your private world remains hidden from logic which "#include"s your public class header.
When you change your private methods (the implementation), you are changing the stuff hidden beneath the Pimpl and therefore clients of your class don't need to recompile because from their perspective nothing has changed: They no longer see the private implementation members.
http://www.gotw.ca/gotw/028.htm
回答7:
Not all classes benefit from p-impl. Your example has only primitive types in its internal state which explains why there's no obvious benefit.
If any of the members had complex types declared in another header, you can see that p-impl moves the inclusion of that header from your class's public header to the implementation file, since you form a raw pointer to an incomplete type (but not an embedded field nor a smart pointer). You could just use raw pointers to all your member variables individually, but using a single pointer to all the state makes memory management easier and improves data locality (well, there's not much locality if all those types use p-impl in turn).
来源：https://stackoverflow.com/questions/3597693/how-does-the-pimpl-idiom-reduce-dependencies