问题
I need a snippet of a batch file that can detect part of a filename, then rename it. Note that the numbers after the filename change randomly but "file" is always the same.
Example:
filename: file143424
There will always be only one file that needs to be renamed in the folder. The script will delete older versions of the file. For instance, I put a first file inside the folder and the script in there too. I then run the script, which renames it to just file. Then if I put a new file in, the script, when run again, will recognize it from the "file" prefix and rename it to file after deleting the old one.
回答1:
Excuse me. Your question is incomplete, I think. You want to rename "file134342" to what?
In your comment you said: rename it to just "file", but this works only if there is just one file with that name. Anyway, here it is:
for %%f in (file*) do ren %%f file
If this is not what you want, then give us more details (you showld always give full details from the very beginning).
回答2:
You can check for the first four characters that way:
if "%filename:~0,4%"=="file" ...
回答3:
@Aacini's suggestion should work fine in your case. But you could do very well without a for loop, a single REN (RENAME) command would be enough:
RENAME file* file
来源：https://stackoverflow.com/questions/10969981/batch-file-to-detect-only-part-of-a-filename