问题
I want to change the ACL of a file and set "full permissions" to a special user.
I know the cacls-command cacls . /e /t /p Everyone:f
But this only works if the OS is english. For german systems, it must be
cacls . /e /t /p Jeder:f
.
I know the well-known SIDs of the user "everyone" (S-1-1-0), but it seems as if I can't use them with cacls.
I tried cacls . /e /t /p S-1-1-0:f
.
Is there a way to use windows command line tools for this jobs? I'm not allowed to bundle software or other commandline tools for this job with my software.
The solution has to be called from a Java-Process, but that should not be a problem.
回答1:
This might be Windows version specific, but look at
whoami /groups
and parse the result. On Windows 7, this
whoami /groups | find "S-1-1-0"
looks like this for me
C:\>whoami /groups | find "S-1-1-0"
Everyone Well-known group S-1-1-0
Mandatory group, Enabled by default, Enabled group
There's a whole Win32 API for getting at this. Here's a solution using that from C#
http://www.ms-news.net/f2438/setpermission-everyone-c-4997971.html
回答2:
I found a solution. I am using a library from the vendor of my Setup creation tool.
edit:
Solution for problem:
The Setup-Creation Tool Install4j
has a method getUserLogin(String sid)
its returnvalue is something like: WORKSTATION1\User1
I used cacls
to change the ACL.
来源:https://stackoverflow.com/questions/4389868/how-to-change-the-file-acl-in-windows-if-i-only-know-the-sid