问题
std::auto_ptr lacks const copy constructor, therefore I cannot use it directly in collections. is there some way to have for example vector of std::auto_ptr without using boost pointer collection template?
回答1:
If you have a C++0x compiler you can use shared_ptr or unique_ptr as appropriate.
There is a good example of correct unique_ptr usage here courtesy of @James McNellis. For a shared_ptr walkthrough look here, courtesy of @D.Shawley. [Upvotes would still be appreciated on those threads, I am sure.]
vector of auto_ptr is always invalid, although Visual C++ v6 disagreed.
回答2:
No, you just can't have a vector of std::auto_ptr, though there exist many speculations that you can. But if your compiler supports C++0x, you can use std::unique_ptr, which is the new alternative of the deprecated auto pointer which, quote from the new standard, provides a superior alternative. See also this thread
回答3:
auto_ptr is designed for auto deletion when a variable leaves scope. You don't want to use it in a collection, instead as mentioned above you want to use something like shared_ptr.
Example of auto_ptr's typical use:
void foo()
{
auto_ptr<int> bar = auto_ptr<int>(new int);
...
return; //memory held by auto_ptr is automatically deleted
}
Anything beyond this use is potentially dangerous and/or broken if you are not sure of the special semantics of auto_ptr. (Edit: clarify based on Armen's comment)
来源：https://stackoverflow.com/questions/3971818/c-stdauto-ptr-copy-constructor