问题
I am working with GAE and have a user table. Now I want to model friend relationships between users. I am thinking of having 3 properties user1, user2 and request_status, but the problem is in querying to find a particular user's friends. Since GAE does not allow OR filtering, I have to merge two queries. Clearly that is very inefficient. This is just one problem with my approach.
If someone could suggest a solution that lets me keep track of all friend requests as well as the friendship, then that would be very helpful.
回答1:
Denormalization will let you more efficiently find a user's friends with a single query. Try storing another property users (a db.ListProperty) in your model which contains both user1 and user2. Then you can simply execute a query like this to find a user's friends:
friendships = Friendship.all().filter('users =', user).fetch(...)
The advantage is that you only need a single query (faster). The disadvantage is that you will have a little extra space overhead to store the users property and the (automatic) index on it.
来源：https://stackoverflow.com/questions/4202059/modeling-a-friend-relationship-in-gae