Pandas, dataframe with a datetime64 column, querying by hour

若如初见. 提交于 2019-12-06 12:10:51

问题


I have a pandas dataframe df which has one column constituted by datetime64, e.g.

<class 'pandas.core.frame.DataFrame'>
Int64Index: 1471 entries, 0 to 2940
Data columns (total 2 columns):
date    1471  non-null values
id      1471  non-null values
dtypes: datetime64[ns](1), int64(1)

I would like to sub-sample df using as criterion the hour of the day (independently on the other information in date). E.g., in pseudo code

df_sub = df[ (HOUR(df.date) > 8) & (HOUR(df.date) < 20) ]

for some function HOUR.

I guess the problem can be solved via a preliminary conversion from datetime64 to datetime. Can this be handled more efficiently?


回答1:


Found a simple solution.

df['hour'] = df.date.apply(lambda x : x.hour)

df_sub = df[(df.hour > 8) & (df.hour) <20]

EDIT:

There is a property dt specifically introduced to handle this problem. The query becomes:

df_sub = df[ (df.date.dt.hour > 8) 
              &  (df.date.dt.hour < 20) ]


来源:https://stackoverflow.com/questions/21624217/pandas-dataframe-with-a-datetime64-column-querying-by-hour

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!