问题
I have nested multidimensional arrays that may be 2 or 3 levels deep. Inside it I may or may not have list arrray. I need to loop over the array:
Array
(
[0] => Array
(
[id] => 1
[name] => cat_name_1
[list] => Array
(
[1] => swgdgbdg
[2] => xcbcxb
)
)
[1] => Array
(
[id] => 3
[name] => cat_name_3
[list] => Array
(
[0] => Array
(
[id] => 1
[name] => cat_name_1
[list] => Array
(
[1] => 543h54h
[2] => 54hrhhfr2
)
)
[1] => Array
(
[id] => 2
[name] => cat_name_2
[list] => Array
(
[1] => eherfherh
[2] => 4564642
)
)
[2] => Array
(
[1] => erggb45yt
[2] => jyuk768k
)
[3] => Array
(
[1] => sdgsdgsdg
[2] => 4tg34g34g
)
)
)
and store the following in another array:
array (
0 => array (
[1] => swgdgbdg
[2] => xcbcxb
) ,
1 => array(
[1] => 543h54h
[2] => 54hrhhfr2
) ,
2 => array(
[1] => eherfherh
[2] => 4564642
),
3 => array(
[1] => erggb45yt
[2] => jyuk768k
),
4 => array(
[1] => sdgsdgsdg
[2] => 4tg34g34g
)
);
回答1:
You can use array_walk_recursive() to get the key 1,2 and are not array element, like this, check the live demo here.
$result = [];
$temp = [];
array_walk_recursive($array, function($v, $k) use(&$result, &$temp){
if($k == 1)
$temp[$k] = $v;
if($k == 2)
{
$temp[$k] = $v;
$result[] = $temp;
}
});
print_r($result);
Edit for unfixed length and unordered index, live demo.
Extend the array_walk_recursive() with a third parameter for the callfunction to indicate if it's at the start of an subarray.
$result = [];
$temp = [];
$length = 0;
uarray_walk_recursive($array, function($v, $k, $f) use(&$result, &$temp, &$length){
if(is_numeric($k)) {
if($f && $length != 0) {
$result[] = $temp;
$length = 0;
$temp = [];
}
$temp[$k] = $v;
$length++;
}
});
$result[] = $temp;
print_r($result);
function uarray_walk_recursive(&$input, $funcname)
{
if (!is_callable($funcname)) {
if (is_array($funcname)) {
$funcname = $funcname[0] . '::' . $funcname[1];
}
user_error('uarray_walk_recursive() Not a valid callback ' . $user_func,
E_USER_WARNING);
return;
}
if (!is_array($input)) {
user_error('uarray_walk_recursive() The argument should be an array',
E_USER_WARNING);
return;
}
$args = func_get_args();
$flag = true;
foreach ($input as $key => $item) {
if (is_array($item)) {
$args[2] = false;
$flag = true;
uarray_walk_recursive($item, $funcname, $args);
$input[$key] = $item;
} else {
$args[2] = $flag;
$flag = false;
$args[0] = &$item;
$args[1] = &$key;
call_user_func_array($funcname, $args);
$input[$key] = $item;
}
}
}
回答2:
PseudoCode
function getSomething(var arr)
{
flag = 0;
output = []
for( i = 0 to arr.length)
{
check arr[i] is array,
if yes,then flag = 1 and output.add(getSomething(arr[i]))
if not, continue
}
if flag =0,then return arr
else return output;
}
来源:https://stackoverflow.com/questions/44537419/multidimensional-array-store-each-list-array-inside-another-array