问题
I'm working on a project that uses OpenGL 4.0 shaders.
I have to supply the call to glShaderSource() with an array of char arrays, which represents the source of the shader.
The shader compilation is failing, with the following errors:
(0) : error C0206: invalid token "<null atom>" in version line
(0) : error C0000: syntax error, unexpected $end at token "<EOF>"
Here's my (hello world) shader - straight from OpenGL 4.0 shading language cookbook
#version 400
in vec3 VertexPosition;
in vec3 VertexColor;
out vec3 Color;
void main()
{
Color = VertexColor;
gl_Position = vec4( VertexColor, 1.0 );
}
And here's my code to read the shader file into my C++ code, and compile the shader at runtime:
const int nMaxLineSize = 1024;
char sLineBuffer[nMaxLineSize];
ifstream stream;
vector<string> vsLines;
GLchar** ppSrc;
GLint* pnSrcLineLen;
int nNumLines;
stream.open( m_sShaderFile.c_str(), std::ios::in );
while( (stream.good()) && (stream.getline(sLineBuffer, nMaxLineSize)) )
{
if( strlen(sLineBuffer) > 0 )
vsLines.push_back( string(sLineBuffer) );
}
stream.close();
nNumLines = vsLines.size();
pnSrcLineLen = new GLint[nNumLines];
ppSrc = new GLchar*[nNumLines];
for( int n = 0; n < nNumLines; n ++ )
{
string & sLine = vsLines.at(n);
int nLineLen = sLine.length();
char * pNext = new char[nLineLen+1];
memcpy( (void*)pNext, sLine.c_str(), nLineLen );
pNext[nLineLen] = '\0';
ppSrc[n] = pNext;
pnSrcLineLen[n] = nLineLen+1;
}
vsLines.clear();
// just for debugging purposes (lines print out just fine..)
for( int n = 0; n < nNumLines; n ++ )
ATLTRACE( "line %d: %s\r\n", n, ppSrc[n] );
// Create the shader
m_nShaderId = glCreateShader( m_nShaderType );
// Compile the shader
glShaderSource( m_nShaderId, nNumLines, (const GLchar**)ppSrc, (GLint*) pnSrcLineLen );
glCompileShader( m_nShaderId );
// Determine compile status
GLint nResult = GL_FALSE;
glGetShaderiv( m_nShaderId, GL_COMPILE_STATUS, &nResult );
The C++ code executes as expected, but the shader compilation fails. Can anyone spot what I might be doing wrong?
I have a feeling that this may be to do with end of line characters somehow, but as this is my first attempt at shader compilation, I'm stuck!
I've read other SO answers on shader compilation, but they seem specific to Java / other languages, not C++. If it helps, I'm on the win32 platform.
回答1:
Just a quick hunch:
Have you tried calling glShaderSource with NULL as length parameter? In that case OpenGL will assume your code to be null-terminated.
(Edited because of stupidity)
回答2:
You have made a mistake that others have made. This is the definition of glShaderSource:
void glShaderSource(GLuint shader, GLsizei count, const GLchar **string, const GLint *length);
The string is an array of strings. It is not intended to be an array of lines in your shader. The way the compiler will interpret this array of strings is by concatenating them together, one after another. Without newlines.
Since stream.getline will not put the \n character in the string, each of the shader strings you generate will not have a newline at the end. Therefore, when glShaderSource goes to compile them, your shader will look like this:
#version 400in vec3 VertexPosition;in vec3 VertexColor;out vec3 Color;...
That's not legal GLSL.
The proper way to do this is to load the file as a string.
std::ifstream shaderFile(m_sShaderFile.c_str());
if(!shaderFile)
//Error out here.
std::stringstream shaderData;
shaderData << shaderFile.rdbuf(); //Loads the entire string into a string stream.
shaderFile.close();
const std::string &shaderString = shaderData.str(); //Get the string stream as a std::string.
Then you can just pass that along to glShaderSource easily enough:
m_nShaderId = glCreateShader( m_nShaderType );
const char *strShaderVar = shaderString.c_str();
GLint iShaderLen = shaderString.size();
glShaderSource( m_nShaderId, 1, (const GLchar**)&strShaderVar, (GLint*)&iShaderLen );
glCompileShader( m_nShaderId );
If you copied this loading code from somewhere, then I strongly suggest you find a different place to learn about OpenGL. Because that's terrible coding.
回答3:
glShaderSource( m_nShaderId, nNumLines, (const GLchar**)ppSrc, (GLint*) pnSrcLineLen );
I know the signature of glShaderSource looks tempting to send each line of the shader separately. But that's now what it's meant for. The point of being able to send is multiple arrays is so that one can mix multiple primitive shader sources into a single shader, kind of like include files. Understanding this, makes it much simpler to read in a shader file – and avoids such nasty bugs.
Using C++ you can do it much nicer and cleaner. I already wrote the follwing in Getting garbage chars when reading GLSL files
You're using C++, so I suggest you leverage that. Instead of reading into a self allocated char array I suggest you read into a std::string:
#include <string>
#include <fstream>
std::string loadFileToString(char const * const fname)
{
std::ifstream ifile(fname);
std::string filetext;
while( ifile.good() ) {
std::string line;
std::getline(ifile, line);
filetext.append(line + "\n");
}
return filetext;
}
That automatically takes care of all memory allocation and proper delimiting -- the keyword is RAII: Resource Allocation Is Initialization. Later on you can upload the shader source with something like
void glcppShaderSource(GLuint shader, std::string const &shader_string)
{
GLchar const *shader_source = shader_string.c_str();
GLint const shader_length = shader_string.size();
glShaderSource(shader, 1, &shader_source, &shader_length);
}
You can use those two functions together like this:
void load_shader(GLuint shaderobject, char * const shadersourcefilename)
{
glcppShaderSource(shaderobject, loadFileToString(shadersourcefilename));
}
来源：https://stackoverflow.com/questions/8024433/glsl-shader-compilation-issue-at-runtime