How Can I Fill These Squares in Turtle - Python

Question

I am trying to fill the color in these squares:

Right now the turtle only fills the corners of theses squares, not the entire square.

Here is my code:

import turtle
import time
import random

print ("This program draws shapes based on the number you enter in a uniform pattern.")
num_str = input("Enter the side number of the shape you want to draw: ")
if num_str.isdigit():
    squares = int(num_str)

angle = 180 - 180*(squares-2)/squares

turtle.up

x = 0 
y = 0
turtle.setpos(x,y)


numshapes = 8
for x in range(numshapes):
    turtle.color(random.random(),random.random(), random.random())
    x += 5
    y += 5
    turtle.forward(x)
    turtle.left(y)
    for i in range(squares):
        turtle.begin_fill()
        turtle.down()
        turtle.forward(40)
        turtle.left(angle)
        turtle.forward(40)
        print (turtle.pos())
        turtle.up()
        turtle.end_fill()

time.sleep(11)
turtle.bye()

I've tried moving around turtle.begin_fill() and end_fill() in numerous locations with no luck… Using Python 3.2.3, thanks.

Answer 1

I haven't really used turtle, but it look like may this is what you want to do. Correct me if I've assumed the wrong functionality for these calls:

turtle.begin_fill() # Begin the fill process.
turtle.down() # "Pen" down?
for i in range(squares):  # For each edge of the shape
    turtle.forward(40) # Move forward 40 units
    turtle.left(angle) # Turn ready for the next edge
turtle.up() # Pen up
turtle.end_fill() # End fill.

Answer 2

You're drawing a series of triangles, using begin_fill() and end_fill() for each one. What you can probably do is move your calls to begin_fill() and end_fill() outside the inner loop, so you draw a full square and then ask for it to be filled.

Answer 3

Use fill

t.begin_fill()
t.color("red")
for x in range(4):
    t.fd(100)
    t.rt(90)
t.end_fill()

Answer 4

great that you solved it! if you want to make turtle programming easier, use turtle.seth instead of turtle.left or right. turtle.left is relative to the turtle's last position, so you dont have to worry about where the turtle was facing before a command