问题
I would like to copy some files in a directory, renaming the files but conserving extension. Is this possible with a simple cp, using regex ?
For example :
cp ^myfile\.(.*) mydir/newname.$1
So I could copy the file conserving the extension but renaming it. Is there a way to get matched elements in the cp regex to use it in the command ?
If not, I'll do a perl script I think, or if you have another way...
Thanks
回答1:
Suppose you have myfile.a, myfile.b, myfile.c:
for i in myfile.*; do echo mv "$i" "${i/myfile./newname.}"; done
This creates (upon removal of echo) newname.a, newname.b, newname.c.
回答2:
The shell doesn't understand general regexes; you'll have to outsource to auxiliary programs for that. The classical scripty way to solve your task would be something like
for a in myfile.* ; do
b=`echo $a | sed 's!^myfile!mydir/newname!'`
cp $a $b
done
Or have a perl script generate a list of commands that you then source into the shell.
回答3:
I really like the regex syntax of the rename perl script (by Robin Barker and Larry Wall), e.g.:
rename "s/OldFile/NewFile/" OldFile*
OldFile.candOldFile.hare renamed toNewFile.candNewFile.h, respectively
I simply wanted the exact same thing with a copy command:
copy "s/OldFile/NewFile/" OldFile*
So I duplicated that script and changed the rename statement to copy via File::Copy. Et voila! A copy command with perl-regex syntax:
https://gist.github.com/jcward/0ead33bd79f2061c68728cc82582241f
来源:https://stackoverflow.com/questions/7135324/linux-cp-with-a-regexp