YAML

Read and merge two Yaml files

由 |▌冷眼眸甩不掉的悲伤 提交于 2021-02-07 20:40:25
问题 Assuming we have two yaml files master.yaml someProperty: "someVaue" anotherProperty: "anotherValue" override.yaml someProperty: "overriddenVaue" Is it possible to unmarshall, merge, and then write those changes to a file without having to define a struct for every property in the yaml file? The master file has over 500 properties in it that are not at all important to the service at this point of execution, so ideally I'd be able to just unmarshal into a map, do a merge and write out in yaml

Read and merge two Yaml files

由 旧城冷巷雨未停 提交于 2021-02-07 20:38:20
问题 Assuming we have two yaml files master.yaml someProperty: "someVaue" anotherProperty: "anotherValue" override.yaml someProperty: "overriddenVaue" Is it possible to unmarshall, merge, and then write those changes to a file without having to define a struct for every property in the yaml file? The master file has over 500 properties in it that are not at all important to the service at this point of execution, so ideally I'd be able to just unmarshal into a map, do a merge and write out in yaml

How do I make Swagger-UI use a YAML/JSON rather than having to put annotations on my REST controller?

由 一笑奈何 提交于 2021-02-07 18:25:57
问题 I am used to adding annotations on my REST controllers for Swagger-UI to use. However, I would prefer to point Swagger-UI at a YAML file which describes my REST controller. An example of what I want to do is shown below. (Springfox/Swagger2) DemoApplication.java import org.springframework.boot.SpringApplication; import org.springframework.boot.autoconfigure.SpringBootApplication; @SpringBootApplication public class DemoApplication { public static void main(String[] args) { SpringApplication

How do I make Swagger-UI use a YAML/JSON rather than having to put annotations on my REST controller?

由 ≡放荡痞女 提交于 2021-02-07 18:25:09
问题 I am used to adding annotations on my REST controllers for Swagger-UI to use. However, I would prefer to point Swagger-UI at a YAML file which describes my REST controller. An example of what I want to do is shown below. (Springfox/Swagger2) DemoApplication.java import org.springframework.boot.SpringApplication; import org.springframework.boot.autoconfigure.SpringBootApplication; @SpringBootApplication public class DemoApplication { public static void main(String[] args) { SpringApplication

Turning off requestLog

由 ▼魔方 西西 提交于 2021-02-07 13:45:39
问题 We just upgraded our dropwizard version from 0.6.2 or 0.7 and found out that a lot of configurations have changed in .yml file. Although we were able to figure out most of them, we cannot figure out how to turn off the "requestLog". In 0.6.2 we did the following: requestLog: # Settings for logging to stdout. console: # If true, log requests to stdout. enabled: false # The time zone in which dates should be displayed. But looking at the new documentation: we do not see any reference to how we

Turning off requestLog

由 不打扰是莪最后的温柔 提交于 2021-02-07 13:44:04
问题 We just upgraded our dropwizard version from 0.6.2 or 0.7 and found out that a lot of configurations have changed in .yml file. Although we were able to figure out most of them, we cannot figure out how to turn off the "requestLog". In 0.6.2 we did the following: requestLog: # Settings for logging to stdout. console: # If true, log requests to stdout. enabled: false # The time zone in which dates should be displayed. But looking at the new documentation: we do not see any reference to how we

@ConditionalOnProperty for multi-valued properies

由 ＊爱你＆永不变心＊ 提交于 2021-02-07 13:13:50
问题 Is there any way to use @ConditionalOnProperty annotation based on multi-valued property? Spring configuration: @Bean @ConditionalOnProperty(name = "prop", havingValue = "a") public SomeBean bean1() { return new SomeBean1(); } @Bean @ConditionalOnProperty(name = "prop", havingValue = "b") public SomeBean bean2() { return new SomeBean2(); } and application.yaml prop: - a - b I expect that both beans: bean1 and bean2 will be registered in the spring context, but no one from them isn't

How can I create a yaml file from pure python?

由 强颜欢笑 提交于 2021-02-07 12:20:14
问题 Example from Using YAML with Python Original YAML file contains this # tree format treeroot: branch1: name: Node 1 branch1-1: name: Node 1-1 branch2: name: Node 2 branch2-1: name: Node 2-1 After loading the content from the file using yaml.load() , and dump it into a new YAML file, I get this instead: # tree format treeroot: branch1: branch1-1: {name:Node 1-1} name: Node 1 branch2: branch2-1: {name: Node 2-1} name: Node 2 What is the proper way of building up a YAML file straight from pure

OpenApi required property in nested objects not working

由 断了今生、忘了曾经 提交于 2021-02-07 06:44:06
问题 I need to describe an api having in request body an object with required fields and one of these fields it's an object itself having another set of required fields. I'm using open api v3 and swagger editor (https://editor.swagger.io/) After i put my .yaml file onto the editor I generate an html client (> generate client > html). Then I open the static page index.html generated in the .zip file obtaning this schema: Table of Contents body secureoauthservicesv2Nested_nestedobj body id Integer

flutter使用provider简单实现计数器

由 走远了吗. 提交于 2021-02-06 14:31:37
1，首先在pubspec.yaml里面安装 2，在同一个页面创建两个widget（或者将这两个widget单独创立dart文件） import 'package:flutter/material.dart'; import 'dart:async'; import 'package:provider/provider.dart'; import '../../provide/cunter.dart'; class StrictsSelection extends StatelessWidget { @override Widget build(BuildContext context) { return Scaffold( body: Center( child: Column( children: [ Number(), MyButton() ], ), ), ); } } class Number extends StatelessWidget { @override Widget build(BuildContext context) { return Container( margin: EdgeInsets.only(top: 200), child: Text("${Provider.of<Counter>(context).value}"), ); } } class
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