xor

来源： https://stackoverflow.com/questions/21034107/xor-operator-in-c

来源： https://stackoverflow.com/questions/14461011/xor-between-floats-in-python

来源： https://stackoverflow.com/questions/14461011/xor-between-floats-in-python

来源： https://stackoverflow.com/questions/14461011/xor-between-floats-in-python

来源： https://stackoverflow.com/questions/36655974/what-is-the-difference-between-xor-and-or-in-haskell

来源： https://stackoverflow.com/questions/36655974/what-is-the-difference-between-xor-and-or-in-haskell

问题 I have spent the last 5 hours searching for an answer. Even though I have found many answers they have not helped in any way. What I am basically looking for is a mathematical, arithmetic only representation of the bitwise XOR operator for any 32bit unsigned integers. Even though this sounds really simple, nobody (at least it seems so) has managed to find an answer to this question. I hope we can brainstorm, and find a solution together. Thanks. 回答1: XOR any numerical input a + b - ab(1 + a +

问题 I am looking for a way to get the Bitwise XOR of two images on the command line(or in another way that can be implemented in a program or script). This should result in the same final picture as using the XOR Blending mode in picture editors that support it (Paint.NET, Photoshop, etc) As an example, say I have Image A: and Image B: then the result should look like: The fun part of this is of course, that when you XOR image C with image B again, you will get an exact copy of image A. Now, I

问题 i want to make a program like the following picture and this is my code <?php $iv = 0; $Kunci = "U"; $key = dechex(ord($Kunci)); $k = sprintf("%08d",decbin(hexdec($key))); $c0 = sprintf("%08d", decbin($iv)); $Cip= "0C52CCD7EDB3"; $Cbs = array(); $Cbs[0]= $c0; $Plaintext = array(); $Cas = array(); $P = array(); $m= 1; $n=1; //$Cbs= $Csplit = str_split($Cip, 2); $Cas= str_split($Cip,2); for ($i=0; $i<count($Csplit); $i++) { $Cbs[$m] = sprintf("%08d",decbin(hexdec($Csplit[$i]))); $m++; } for($i

问题 I'm trying to implement XOR in javascript in the following way: // XOR validation if ((isEmptyString(firstStr) && !isEmptyString(secondStr)) || (!isEmptyString(firstStr) && isEmptyString(secondStr)) { alert(SOME_VALIDATION_MSG); return; } Is there a better way to do this in javascript? Thanks. 回答1: I pretend that you are looking for a logical XOR, as javascript already has a bitwise one (^) :) I usually use a simple ternary operator (one of the rare times I use one): if ((isEmptyString