xml-parsing

问题 This is the XML: <?xml version="1.0" encoding="ISO-8859-1"?> <document> <name>Sample Document</name> <type>document</type> <url>http://nsc-component.webs.com/Office/Editor/new-doc.html?docname=New+Document&titletype=Title&fontsize=9&fontface=Arial&spacing=1.0&text=&wordcount3=0</url> </document> <document> <name>Sample</name> <type>document</type> <url>http://nsc-component.webs.com/Office/Editor/new-doc.html?docname=New+Document&titletype=Title&fontsize=9&fontface=Arial&spacing=1.0&text=&<

问题 I am getting an error while executing the query in a SQL Server job. But if I execute it directly, it works fine. Executed as user: NT AUTHORITY\SYSTEM. XML parsing: line 10, character 33 Unexpected end of input [SQLSTATE 42000] (Error 9400). The step failed. SQL Severity 16, SQL Message ID 9400 Code: declare @URL VARCHAR(max) set @url = 'http://www.spa.gov.sa/english/rss.xml' declare @xmlT TABLE (yourXML XML) DECLARE @Response nvarchar(max) DECLARE @XML xml DECLARE @Obj int DECLARE @Result

问题 i guess this is a xml parsing problem, but I just cannot see where it is. I read some articles about this topic and nothing helped: i have this spring mvc config: <?xml version='1.0' encoding='UTF-8' ?> <!-- was: <?xml version="1.0" encoding="UTF-8"?> --> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:p="http://www.springframework.org/schema/p" xmlns:aop="http://www.springframework.org/schema/aop" xmlns:tx="http://www

问题 How to REALLY remove a node via XMLParser: x='''<X> <A> <B c3='1'> <C1>a</C1> <C2>b</C2> </B> <B c3='2'> <C1>e</C1> <C2>e</C2> </B> <B c3='3'> <C1>f</C1> <C2>f</C2> </B> </A> </X> ''' xml=new XmlParser().parseText(x) def nodeToDel=xml.A.B.find{it.@C1='a'} xml.remove(nodeToDel) println xml new XmlNodePrinter(new PrintWriter(new FileWriter(new File('c:/temp/a.xml')))).print(xml) Seems to work BUT!!!! as i translated this to my problem it still saves the original xml althoguh returning true

问题 Using this code to get rss of a site. This code works fine for my computer and many other computers. But in some computers (Windows XP or 7) I get this error: MSXML Not Installed How can I fix this problem? What is wrong? Here is the code: procedure My_Thread.Execute; var http : tidhttp; strm : tmemorystream; str,sTitle, sDec ,er : string; StartItemNode : IXMLNode; ANode : IXMLNode; XMLDoc : IXMLDocument; begin http := tidhttp.Create(); strm := tmemorystream.Create; try http.Get('http://www

问题 Below is the column response from my Postgres table. I want to extract the status from all the rows in my Postgres database. The status could be of varying sizes like SUCCESS as well so I do not want to use the substring function. Is there a way to do it? <?xml version="1.0" ?><response><status>ERROR_MISSING_DATA</status><responseType>COUNTRY_MISSING</responseType><country_info>USA</country_info><phone_country_code>1234</phone_country_code></response> so my table structure is like this Column

问题 Some SVG/XML files I'm working with have dashes and colons in attribute names - for example: <g> <a xlink:href="http://example.com" data-bind="121">...</a> </g> I'm trying to figure out how to unmarshal these attributes using golang's encoding/xml package. While the dashed attributes works, the ones with the colon doesn't: [See here for a live example] package main import ( "encoding/xml" "fmt" ) var data = ` <g> <a xlink:href="http://example.com" data-bind="121">lala</a> </g> ` type Anchor

问题 Some SVG/XML files I'm working with have dashes and colons in attribute names - for example: <g> <a xlink:href="http://example.com" data-bind="121">...</a> </g> I'm trying to figure out how to unmarshal these attributes using golang's encoding/xml package. While the dashed attributes works, the ones with the colon doesn't: [See here for a live example] package main import ( "encoding/xml" "fmt" ) var data = ` <g> <a xlink:href="http://example.com" data-bind="121">lala</a> </g> ` type Anchor

问题 How to create/write a simple XML parser from scratch? Rather than code samples, I want to know what are the simplified, basic steps in English. How is a good parser designed? I understand that regex should not be used in a parser, but how much is regex's role in parsing XML? What is the recommended data structure to use? Should I use linked lists to store and retrieve nodes, attributes, and values? I want to learn how to create an XML parser so that I can write one in D programming language.

问题 how to validate a xml file against a xsd? there is domdocument::schemaValidate() but It does not tell where are the errors. is there any class for that? does it have any worth making that parser from scratch? or is it just reinventing he wheel, 回答1: This code does the business: $xml= new DOMDocument(); $xml->loadXML(<A string goes here containing the XML data>, LIBXML_NOBLANKS); // Or load if filename required if (!$xml->schemaValidate(<file name for the XSD file>)) // Or schemaValidateSource