Really deleting nodes in XMLParser Object Groovy

问题

How to REALLY remove a node via XMLParser:

 x='''<X>
<A>
 <B c3='1'>
   <C1>a</C1>
   <C2>b</C2>
 </B>
 <B c3='2'>
   <C1>e</C1>
   <C2>e</C2>
 </B>
 <B c3='3'>
   <C1>f</C1>
   <C2>f</C2>
 </B>
</A>
</X>
'''

xml=new XmlParser().parseText(x)
def nodeToDel=xml.A.B.find{it.@C1='a'}
xml.remove(nodeToDel)
println xml
new XmlNodePrinter(new PrintWriter(new FileWriter(new File('c:/temp/a.xml')))).print(xml)

Seems to work BUT!!!! as i translated this to my problem it still saves the original xml althoguh returning true after running remove-method.

I googled a little bit and found this BUG. And it seems as i am affected now of that. How can i solve it? Is there a workaround, or do i have to get back to the roots and start to copying it linewise...?? Is groovy really ungroovy here :-/

edit: As written below, and got experience from that, it is not possible to remove the tag where equals 'e' this way. Only the first Record will be removed. I think there is a problem with the xml format. Not having the needed format:

<A x='1' y='2'></A>

and having it in the format

<A> <x>1</x> <y>2</y> </A>

Is somebody able to reproduce this bug?

edit2: I am using the GroovyConsole 1.8.0. Added the c3 attributes to the example. Tried to remove it with same method, same bug: The first B section was removed... Now the most impressing bug: Tried it with other code:

def xml=new XmlParser().parseText(x)
xml.A.remove(xml.A.B.find{it.@'c3'= '3'}) //want to remove third section
new XmlNodePrinter(new PrintWriter(new FileWriter(new File('c:/temp/a.xml')))).print(xml)

results that the first section the property c3 is changed to 3 ?!?!?!?!? wtf...

I am trying to find a solution for a week now, it is quite exhausting...

Somebody an idea?

回答1:

Removing nodes works pretty much like other DOM APIs. You have to pass the node you want to delete to the remove method of its parent.

Also the = operator is the assignment operator in Groovy. it.@C1 = 'a' would assign 'a' to the C1 attribute of each B node in the document. Since the result of that assignment is 'a', which is coerced to true by Groovy, find will always return the first node it encounters.

xml=new XmlParser().parseText(x)
def nodeToDel=xml.A.B.C1.find { it.text() == 'a' }
def parent = nodeToDel.parent()
parent.remove(nodeToDel)

来源：https://stackoverflow.com/questions/7201111/really-deleting-nodes-in-xmlparser-object-groovy

标签

xml

groovy

xml-parsing