xml-parsing

Parse xml using XmlSlurper in Groovy

左心房为你撑大大i 提交于 2019-12-25 07:48:25
问题 I have an xml response which looks like :- <?xml version="1.0" encoding="UTF-8"?> <soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> <soapenv:Body> <multiRef xmlns:ns9="http://hero.ar.vixo.in" xmlns:soapenc="http://schemas.xmlsoap.org/soap/encoding/" id="id2" soapenc:root="0" soapenv:encodingStyle="http://schemas.xmlsoap.org/soap/encoding/" xsi:type="ns9:IdentityModel">

DOM - Accessing inner elements of the same name in java

心已入冬 提交于 2019-12-25 07:39:48
问题 I have an xml file that has many <dict> elements and I want to try get the elements in the third element. My problem is that when I'm calling doc.getElementsByTagName("dict") It gets every element that is called dict. Here is the code: try { File inputFile = new File("itunes2.xml"); DocumentBuilderFactory dbFactory = DocumentBuilderFactory .newInstance(); DocumentBuilder dBuilder = dbFactory.newDocumentBuilder(); Document doc = dBuilder.parse(inputFile); doc.getDocumentElement().normalize();

Can't Retrieve Values of XML Elements using XElement

送分小仙女□ 提交于 2019-12-25 07:35:08
问题 I am trying to read from an XML file that is supplied through a file browser but the values are alwas null even though I can see the xml file come through to elements. public void UploadXml(Stream fileStream) { //Load xml fileStream.Position = 0; var xdoc = XElement.Load(fileStream); IEnumerable<XElement> elements = xdoc.Elements(); var codeList = new CodeList(); foreach (var item in elements) { codeList.Name = item.Element("CODELIST_NAME").Value; codeList.Description = item.Element(

Output of Xpath Query

折月煮酒 提交于 2019-12-25 07:09:01
问题 First I would like to ask what is the format of the output of the Xpath query. For me when I do the view source of my output I get view-source actual output - output Sample xml - xmlfile My php code - <?php $variable=$_POST['module']; $xmldoc = new DOMDocument(); $xmldoc->load('info.xml'); $xpathvar = new Domxpath($xmldoc); $queryResult = $xpathvar->query("testcase[substring-after( substring-after(script, '/'), '/' ) = '$variable' or substring-before( substring-after( substring-after(script,

How to know if a DOMDocument is owned by a parser

|▌冷眼眸甩不掉的悲伤 提交于 2019-12-25 06:23:04
问题 I am looking into an issue where an API is getting called from two different sources. We have an API called dispatch. Its signature is as follows. DOMDocument* dispatch( DOMDocument * requestDocument ) We observed that this API can be called by passing a DOMDocument object that is A stand-alone DOMDocument object created using DOMImplementation::createDocument http://xerces.apache.org/xerces-c/apiDocs-3/classDOMImplementation.html A parse owned DOMDocument object created using

How to know if a DOMDocument is owned by a parser

余生长醉 提交于 2019-12-25 06:22:20
问题 I am looking into an issue where an API is getting called from two different sources. We have an API called dispatch. Its signature is as follows. DOMDocument* dispatch( DOMDocument * requestDocument ) We observed that this API can be called by passing a DOMDocument object that is A stand-alone DOMDocument object created using DOMImplementation::createDocument http://xerces.apache.org/xerces-c/apiDocs-3/classDOMImplementation.html A parse owned DOMDocument object created using

Getting “null” in place of textvalue After parsing XML using PullParser in Android

折月煮酒 提交于 2019-12-25 05:27:17
问题 I had a look at this. SO please dont redirect me to that site. I had already used DOM parser and here is my problem with that. I am having the same XML : <MyResource> <Item>First</Item> <Item>Second</Item> </MyResource> And now i have no way but to parse this XML via PullParser. My methods as taken from this: private List readFeed(XmlPullParser parser) throws XmlPullParserException, IOException { // TODO Auto-generated method stub List entries = new ArrayList(); parser.require(XmlPullParser

How to read and store XML data in database

微笑、不失礼 提交于 2019-12-25 04:46:10
问题 I am very new joiner in java and xml parser, I need to read data from an XMl file and store it in database. Firstly what I did is I have read data from an Xml fileand will store in in text file in Column and row format. Can any one please tell me how can read data from an xml file and manipulate data in form of column and rows. Column and rows means: The Node names must be displayed in header postion in row wise one after the other Example: Column1, column2, column3..... The values in that

In Perl, XML::Simple is not able to dereference multi dimensional associative array parsed by Data::Dumper

无人久伴 提交于 2019-12-25 04:29:25
问题 Following is the xml file that I want to parse: <?xml version="1.0" encoding="UTF-8"?> <topic id="yerus5" xmlns:ditaarch="http://dita.oasis-open.org/architecture/2005/"> <title/> <shortdesc/> <body> <p><b>CCU_CNT_ADDR: (Address=0x004 Reset=32'h1)</b><table id="table_r5b_1xj_ts"> <tgroup cols="4"> <colspec colnum="1" colname="col1"/> <colspec colnum="2" colname="col2"/> <colspec colnum="3" colname="col3"/> <colspec colnum="4" colname="col4"/> <tbody> <row> <entry>Field</entry> <entry>OFFSET<

How do I download xml from the internet in C++

南楼画角 提交于 2019-12-25 04:17:33
问题 The same way an internet browser does it when you save page as .xml, or view page source. Of course I am targeting a webpage that is in xml and starts like this: <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> Why do I want to do this? Well I want to dump the entire source of certain webpages into a string or CString, which I'm still figuring out how to do 回答1: Since you mentioned