view

How to reload a ui view's content Swift

≯℡__Kan透↙ 提交于 2021-01-17 16:00:43
问题 I have a view controller which has scroll view in it, and the scroll view has a view. So, view has a lot of buttons and labels which are being showed depending on data which comes from api. And I have a button after pressing it, I want to reload a views (it's content). 回答1: one of the easy hack and NOT the recommended way is to do self.view.setNeedsLayout() also you can do self.viewDidLoad() OR self.viewWillAppear(true) well the different recommended approaches you can use are the following

How to reload a ui view's content Swift

跟風遠走 提交于 2021-01-17 16:00:40
问题 I have a view controller which has scroll view in it, and the scroll view has a view. So, view has a lot of buttons and labels which are being showed depending on data which comes from api. And I have a button after pressing it, I want to reload a views (it's content). 回答1: one of the easy hack and NOT the recommended way is to do self.view.setNeedsLayout() also you can do self.viewDidLoad() OR self.viewWillAppear(true) well the different recommended approaches you can use are the following

create oracle view based on comparision of data between two database tables

ⅰ亾dé卋堺 提交于 2021-01-04 05:34:30
问题 I have below tables: I want to create View such that for descr = 'O' and for common id_isin field value from both tables, check the ratio field and take only the row where ratio field value is low. for descr = 'O' and if the id_isin exist in one table but not in another then take those rows(bidirectional) For all the rows where descr ! = 'O' , take all those rows from table IS_ID_TST . Below is the expected output from view for example: ID_ISIN QUOTE_CRNY DESCR RATIO ALLOCATIONASSETTYPE

create oracle view based on comparision of data between two database tables

妖精的绣舞 提交于 2021-01-04 05:34:22
问题 I have below tables: I want to create View such that for descr = 'O' and for common id_isin field value from both tables, check the ratio field and take only the row where ratio field value is low. for descr = 'O' and if the id_isin exist in one table but not in another then take those rows(bidirectional) For all the rows where descr ! = 'O' , take all those rows from table IS_ID_TST . Below is the expected output from view for example: ID_ISIN QUOTE_CRNY DESCR RATIO ALLOCATIONASSETTYPE

create oracle view based on comparision of data between two database tables

点点圈 提交于 2021-01-04 05:33:51
问题 I have below tables: I want to create View such that for descr = 'O' and for common id_isin field value from both tables, check the ratio field and take only the row where ratio field value is low. for descr = 'O' and if the id_isin exist in one table but not in another then take those rows(bidirectional) For all the rows where descr ! = 'O' , take all those rows from table IS_ID_TST . Below is the expected output from view for example: ID_ISIN QUOTE_CRNY DESCR RATIO ALLOCATIONASSETTYPE

create oracle view based on comparision of data between two database tables

放肆的年华 提交于 2021-01-04 05:33:06
问题 I have below tables: I want to create View such that for descr = 'O' and for common id_isin field value from both tables, check the ratio field and take only the row where ratio field value is low. for descr = 'O' and if the id_isin exist in one table but not in another then take those rows(bidirectional) For all the rows where descr ! = 'O' , take all those rows from table IS_ID_TST . Below is the expected output from view for example: ID_ISIN QUOTE_CRNY DESCR RATIO ALLOCATIONASSETTYPE

View presented twice in SwiftUI on iOS 14

天大地大妈咪最大 提交于 2021-01-01 06:52:05
问题 I need to dynamically present views based on a model so the decision of which view to present and the creation of the views needs to be external to the SwiftUI views. This is working well on iOS 13 but on iOS 14 the first view presents again instead of the second view, although the second view does get initialised as expected the first view is pushed onto the navigation stack a second time. It seems like a iOS 14 bug but perhaps I'm doing something wrong so asking here before filing a bug

How To Position Views Relative To Their Top Left Corner In SwiftUI

≡放荡痞女 提交于 2020-12-26 09:13:25
问题 How do I position views relative to their top left corner in swiftUI? The "position" modifier moves the views relative to their center coordinates. So .position(x: 0, y: 0) places a views center coordinate in the top left of the screen. I want to place a views top left coordinate in the top left of the screen, How do I do this? struct HomeView: View { var body: some View { VStack(alignment: .leading) { Text("Top Text") .font(.system(size: 20)) .fontWeight(.medium) Text("Bottom Text") .font(

How To Position Views Relative To Their Top Left Corner In SwiftUI

别来无恙 提交于 2020-12-26 09:10:46
问题 How do I position views relative to their top left corner in swiftUI? The "position" modifier moves the views relative to their center coordinates. So .position(x: 0, y: 0) places a views center coordinate in the top left of the screen. I want to place a views top left coordinate in the top left of the screen, How do I do this? struct HomeView: View { var body: some View { VStack(alignment: .leading) { Text("Top Text") .font(.system(size: 20)) .fontWeight(.medium) Text("Bottom Text") .font(

MySQL join two table with the maximum value on another field

烂漫一生 提交于 2020-12-25 01:10:07
问题 I have two table account and balance /---------------------\ | cid | name | mobile | |---------------------| | 1 | ABC | 12345 | |---------------------| | 2 | XYZ | 98475 | \---------------------/ /----------------------------\ | date | cid | balance | |----------------------------| | 2013-09-19 | 1 | 5000 | |----------------------------| | 2013-09-19 | 2 | 7000 | |----------------------------| | 2013-09-20 | 1 | 300 | |----------------------------| | 2013-09-20 | 2 | 4500 | |----------------