unsigned

I'm converting an unsigned integer to binary using bitwise operators, and currently do integer & 1 to check if bit is 1 or 0 and output, then right shift by 1 to divide by 2. However the bits are returned in the wrong order (reverse), so I thought to reverse the bits order in the integer before beginning. Is there a simple way to do this? Example: So if I'm given the unsigned int 10 = 1010 while (x not eq 0) if (x & 1) output a '1' else output a '0' right shift x by 1 this returns 0101 which is incorrect... so I was thinking to reverse the order of the bits originally before running the loop,

转载: Android原生(Native)C开发之一 环境搭建篇 转载: Android原生(Native)C开发之二 framebuffer篇 转载: Android原生(Native)C开发之三 鼠标事件篇(捕鼠记) 转载: Android原生(Native)C开发之四 SDL移植笔记 转载: Android原生(Native)C开发之五 zlib移植笔记 转载: Android原生(Native)C开发之六 libpng移植笔记 转载: Android原生(Native)C开发之一 环境搭建篇 2009年02月25日，星期三 Android是基于Linux的操作系统，处理器是ARM的，所以要在Linux或Windows等x86系统上编译Android能运行的程序，你需要一个交叉编译器。 在Linux下面，你可以自已编译一个交叉编译环境，但Windows下面，就比较复杂（也可以在cygwin中编译一个），但你可以选择下载一个现成的交叉编译环境： http://www.codesourcery.com/gnu_toolchains/arm/download.html Windows: http://www.codesourcery.com/gnu_toolchains/arm/portal/package3400/public/arm-none-linux-gnueabi/arm

转：https://segmentfault.com/a/1190000015432946 最近把opus编码器里的VAD算法提取了出来，之前在网上没找到合适的开源VAD模块，就把代码放在这里吧，希望能帮助到人。 下面是.h文件和.cpp文件，使用的时候，需要调用silk_VAD_Get()这个函数，每次输入一个帧（我默认了帧长是20ms，采样率16khz，可以自己在silk_VAD_Get里修改），返回0或者1，代表该帧是否为静音帧。 .h文件代码： #include <stdlib.h> #include <malloc.h> #include <intrin.h> #include <string.h> int silk_VAD_Get( //int state, /* Encoder state */ const short pIn[] /* I PCM input */ ); #define TYPE_NO_VOICE_ACTIVITY 0 #define TYPE_UNVOICED 1 #define TYPE_VOICED 2 #define SPEECH_ACTIVITY_DTX_THRES 0.05f #define SILK_FIX_CONST( C, Q ) ((int)((C) * ((long)1 << (Q)) + 0.5)) #define silk

I've seen this unsigned "typeless" type used a couple of times, but never seen an explanation for it. I suppose there's a corresponding signed type. Here's an example: static unsigned long next = 1; /* RAND_MAX assumed to be 32767 */ int myrand(void) { next = next * 1103515245 + 12345; return(( unsigned )(next/65536) % 32768); } void mysrand( unsigned seed ) { next = seed; } What I have gathered so far: - on my system, sizeof(unsigned) = 4 (hints at a 32-bit unsigned int) - it might be used as a shorthand for casting another type to the unsigned version: signed long int i = -42; printf("%u\n",

I have an unsigned integer but when i print it out using %d there is sometimes a negative value there? LiraNuna Printing %d will read the integer as a signed decimal number, regardless of its defined type. To print unsigned numbers, use %u . This happens because of C's way to handle variable arguments. The compiler just pulls values from the stack (typed as void* and pointing to the call stack) and printf has to figure out what the data contains from the format string you give it to. This is why you need to supply the format string - C has no way of RTTI or a 'base class' ( Object in Java, for

Does C treat hexadecimal constants (e.g. 0x23FE) and signed or unsigned int? The number itself is always interpreted as a non-negative number. Hexadecimal constants don't have a sign or any inherent way to express a negative number. The type of the constant is the first one of these which can represent their value: int unsigned int long int unsigned long int long long int unsigned long long int It treats them as int literals(basically, as signed int!). To write an unsigned literal just add u at the end: 0x23FEu According to cppreference , the type of the hexadecimal literal is the first type

I can never understand how to print unsigned long datatype in C. Suppose unsigned_foo is an unsigned long , then I try: printf("%lu\n", unsigned_foo) printf("%du\n", unsigned_foo) printf("%ud\n", unsigned_foo) printf("%ll\n", unsigned_foo) printf("%ld\n", unsigned_foo) printf("%dl\n", unsigned_foo) And all of them print some kind of -123123123 number instead of unsigned long that I have. %lu is the correct format for unsigned long . Sounds like there are other issues at play here, such as memory corruption or an uninitialized variable. Perhaps show us a larger picture? NealCaffery %lu for