unsigned

Java and unsigned Bytes [duplicate]

最后都变了- 提交于 2019-12-01 21:10:11
This question already has an answer here: What is the best way to work around the fact that ALL Java bytes are signed? 7 answers I need to make use of an array of unsigned bytes. I need to send certain characters over the network to a server and some of these characters are greater that 127. I have a simplified version of the code below to try and understand the concept: int i= 160; byte j = (byte) i; System.out.println((byte)i); System.out.println(j); and this gives an output of: -96 -96 I need to print 160. As the server is expecting a byte of 160 and if it receives -96 it does not accept

Reading 'unsigned int' using 'cin'

孤人 提交于 2019-12-01 17:37:18
I am trying to read an unsigned int using cin as follows: #include <limits.h> #include <iostream> using namespace std; int main(int argc, char* argv[]) { unsigned int number; // UINT_MAX = 4294967295 cout << "Please enter a number between 0 and " << UINT_MAX << ":" << endl; cin >> number; // Check if the number is a valid unsigned integer if ((number < 0) || ((unsigned int)number > UINT_MAX)) { cout << "Invalid number." << endl; return -1; } return 0; } However, whenever I enter a value greater than the upper limit of unsigned integer ( UINT_MAX ), the program displays 3435973836 . How do I

LDD3阅读笔记-字符设备驱动

久未见 提交于 2019-12-01 17:22:34
#主要开发流程介绍 module_init宏和module_exit宏 当模块装载时需要调用module_init宏指定的函数,卸载时需要调用 module_exit宏指定的函数 以下是简单的init流程: 初始化设备 初始化file_operation 获取字符设备号 注册字符设备 当卸载模块时,需要释放申请的设备号。 #主设备号和次设备号 对字符设备的访问是通过文件系统内的设备名称进行的。那些名称被称为特殊 文件、设备文件,或者简单称为文件系统树的节点,他们通常位于/dev目录。 通常而言,主设备号表示设备对应的驱动程序。例如,/dev/null和/dev/zero 由驱动程序1管理,而虚拟控制台和串口终端由驱动程序4管理。 现代的Linux内核允许多个驱动程序共享主设备号,但我们看到的仍然按照”一 个主设备号对应一个驱动程序“的原则组织。 /proc/devices 可以查看注册的主设备号; /proc/modules 可以查看正在使用模块的进程数 #设备编号的内部表达 在内核中dev_t类型(在linux/types.h中定义)用来保存设备编号——包括主 设备号和次设备号。我们的代码不应该对设备编号的组织做任何假定,而应该始终 使用linux/kdev_t.h中定义的宏。 MAJOR(dev_t dev); MINOR(dev_t dev); 相反

What does the unary operator “-” do on unsigned data types in C/C++ (and on different compilers)?

独自空忆成欢 提交于 2019-12-01 17:08:09
问题 For example: unsigned int numA = 66; // or anything really unsigned int numB = -numA; unsigned int numC = numA & numB I understand that the bitwise complement operator can be used to get the two's complement (in conjunction with a +1). The reason I ask is because I stumbled upon this in some code for a chess engine. Chess engines do a lot of 'hacky' things to get absolute speed, especially in the move generation functions that are called millions of times per second. (It doesn't help that it

基于UDP协议获取陀螺仪数据(1)

不羁岁月 提交于 2019-12-01 16:10:19
前一段时间拿到一块板子,上面是一个村田陀螺仪,已经经过硬件接口处理过,上面有一个网口和一个usb口,还有一些串口。我现在需要通过网口来拿到陀螺仪的原始数据。硬件工程师给我的文档如下: 第一步:陀螺仪要供电,该陀螺仪测试为12v直流电! 第二步:设置上位机IP,子网掩码,网关。并连接网络. 其实,上位机就相当于server端,而板子就相当于client端,板子要主动上报,说明client端一直向server端发送数据。 第三步:ping一下板子上的IP,看看能不能ping通,如果ping通了说明连接成功。 第四步:利用命令tcpdump -n -i eth0 host SERVER_IP and CLIENT_IP,看看连接成功后是否有数据传输。 第五步:编写代码实现udp传输数据 1 /************************************************************************* 2 > File Name: client.cpp 3 > Author: 李瀚文 4 > Mail: 18646139976@163.com 5 > Created Time: 2019年10月15日 星期二 08时14分06秒 6 ************************************************************

Bad value affectation after type casting

牧云@^-^@ 提交于 2019-12-01 13:53:21
I am using a native unsigned long variable as a buffer used to contain two unsigned short variable inside it. From my knowledge of C++ it should be a valid method. I used this method to store 2 unsigned char inside one unsigned short many times without any problem. Unfortunately when using it on a different architecture, it react strangely. It seems to update the value after a second assignation. The (Overflow) case is there simply to demonstrate it. Can anyone shed some light on why it react that way? unsigned long dwTest = 0xFFEEDDCC; printf("sizeof(unsigned short) = %d\n", sizeof(unsigned

Bad value affectation after type casting

孤人 提交于 2019-12-01 12:26:50
问题 I am using a native unsigned long variable as a buffer used to contain two unsigned short variable inside it. From my knowledge of C++ it should be a valid method. I used this method to store 2 unsigned char inside one unsigned short many times without any problem. Unfortunately when using it on a different architecture, it react strangely. It seems to update the value after a second assignation. The (Overflow) case is there simply to demonstrate it. Can anyone shed some light on why it react

C: uint16_t subtraction behavior in gcc

霸气de小男生 提交于 2019-12-01 11:21:56
问题 I'm trying to subtract two unsigned ints and compare the result to a signed int (or a literal). When using unsigned int types the behavior is as expected. When using uint16_t (from stdint.h ) types the behavior is not what I would expect. The comparison was done using gcc 4.5. Given the following code: unsigned int a; unsigned int b; a = 5; b = 20; printf("%u\n", (a-b) < 10); The output is 0, which is what I expected. Both a and b are unsigned, and b is larger than a, so the result is a large

CImg笔记

╄→гoц情女王★ 提交于 2019-12-01 10:06:13
这两天需要封装一个简单处理图片相关的DLL供Python/C#调用,因为CImg比较轻量级且易于集成,所以就决定是你了!CImg! 这篇随笔记录一下开发遇到的问题: 扔出网上翻来的入门PDF: https://link.jianshu.com/?t=https://github.com/dtschump/CImg/blob/master/html/CImg_reference_chinese.pdf Q.关于CImg 获取 Stride的问题:   目前没有找到相关函数,只能自己封装一下: int __stdcall Stride(int wid, int spectrum) { int ret = spectrum * wid; if (ret % 4 != 0) { ret = ret + (4 - ret % 4); } std::cout << "stride : " << ret << std::endl; return ret; } 使用示例代码段: CImg<unsigned char> img_dest(800, 600, 1, 3); Stride(img_dest.width(), img_dest.spectrum()); Q.关于CImg 像素数据存储格式的问题: CImg存储像素点的格式不太同于我常用的图形库....采用的是非交错格式存储

牛客 C++刷题day42

做~自己de王妃 提交于 2019-12-01 08:48:17
1 .“优先使用对象组合,而不是继承”是面向对象设计的第二原则。 组合也叫“对象持有”,就是在类中定义另一类型的成员,继承会破坏类的独立性,增加系统的复杂性,一般系统的继承层次不超过3层。组合拥有良好的扩展性,支持动态组合,因此请优先考虑组合方法。 2 .编 译器在为类对象分配栈空间时,会先检查类的析构函数的访问性,其实不光是析构函数,只要是非静态的函数,编译器都会进行检查。如果类的析构函数是私有的,则编译器不会在栈空间上为类对象分配内存。 因此, 将析构函数设为私有,类对象就无法建立在栈(静态)上了,只能在堆上(动态new)分配类对象 。 3 .mutalbe的中文意思是“可变的,易变的”,跟constant(既 C ++中的const)是反义词。 在C++中,mutable也是为了突破const的限制而设置的。被mutable修饰的变量,将永远处于可变的状态,即使在一个const函数中。 我们知道,如果类的成员函数不会改变对象的状态,那么这个成员函数一般会声明成const的。但是,有些时候,我们需要在const的函数里面修改一些跟类状态无关的数据成员,那么这个数据成员就应该被mutalbe来修饰。 4.我了个大草。30也可以实数表示成30. 后面的0可以不用写,或者说小数点后的数字不写就是自动表示为整数。 5. 表达式会包含隐式类型转换,它由编译器自动执行,不需程序员介入。