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问题 I'm having an issue when running a webpage on iOS Safari. I am using the canvas-text library to render text which works perfectly on the following: Ubuntu/Windows -- chrome, firefox Mac -- Safari Android -- default, firefox, opera, dolphin However, it does not work on iPhone . I enabled the javascript console on the iPhone and I get a few errors which read : Javascript: Error undefined TypeError: 'undefined' is not an object The console does not display line numbers, but by placing alert

问题 I am learning the basics of AngularJS and I can´t figure out why this Factory returns an undefined value. It´ my first attempt to create and understand factories. I saw many examples on SO and on the internet but I couldn´ find the solution. I am trying to create an array of strings (colors) on the factory and a button shown in each different view to add one string to the array. But the factory returns undefined so I can´t inject the value to the controllers. Here is the code. index.html

问题 This is my first time working with wordpress and I'm using the version 3.4.1. Since I used http://www.google.com/cse/, my website http://www.unicos.cc stoped working on IE. It starts loading and loading, but if you take a look on scripts you get this error: <script defer onreadystatechange='google.loader.domReady()' src=//:></script> SCRIPT5009: 'google' is undefined www.unicos.cc, line 1 character 1 I'm using this script on my header.php: <script> (function() { var cx =

问题 As you see,undefined is not a keyword in javascript(Is it right?).So we can use it as a variable though I'm sure this is a bad idea.Now my question is why I can't give a value to undefined. Code: var undefined=3; undefined;//still undefined Any suggestions will be thankfull. 回答1: Because in older environments(before JS 1.8.5) it was possible to change the value of undefined, and checking for something that didn't exist was made in a way that was possible to break. It is a common choice to

问题 I'm new to Google maps and I'm trying to set up a basic directions display. I basically do: var Map = new google.maps.Map( Canvas[ 0 ], { center: { lat: -34.397, lng: 150.644 }, zoom: 8 } ); var DService = new google.maps.DirectionsService(); var DDisplay = new google.maps.DirectionsRenderer(); DDisplay.setMap( Map ); As soon as I do DDisplay.setMap( Map ); Chrome shows an error in the console. The error is: Uncaught TypeError: Cannot read property 'stack' of undefined I have tried including

问题 I'm a newbie to programming in C, and I'm having trouble understanding the error that is coming up when I attempt to compile my program. I've got the following program, which is fairly simple and which my professor says is correct: #include <stdio.h> #define TRUE 1 #define FALSE 0 #define BOOL int extern int x; extern BOOL do_exp; int exp_or_log(); main() { x = 10; do_exp = TRUE; printf("2^%d = %d\n", x, exp_or_log()); //should print 1024 x = 145; do_exp = FALSE; printf("log(%d) = %d\n", x,

问题 I have an Access table with a date/time field. I wanted to make a composite Key field out of the date/time field and 3 other text fields in the same format as the matching Key field in another database. So I concatenated the 3 text fields and wrote a User-Defined-Function in a Module to output the date field as a string in the format "YYYYMMDD". Public Function YYYYMMDD(dteDate As Date) As String YYYYMMDD = Format(dteDate, "YYYYMMDD") End Function I can then successfully run my queries in

问题 Sorry guys, I am reading and searching over the web and I cannot find a solution for this :(. If you can please help me :) Thanks. If I hard code position then it works well. I already tried this on several different ways... P.S. I have to create some kind of image gallery ajax page for exercise :) I assume this position variable should be in singleton/static class i guess. I was not able to test this class yet, but I think this will work only for first and last image always :) (in java code

问题 How can you pass parameters into the keydown method from jquery because whenever I use a variable defined elsewhere it returns undefined. I assume its because the #target is window and therefore its not in the scope but even then I have trouble getting it to compare the key.which() with an outside parameter and then assigning it to another property. Example: var a = 38; var b = 0; $(document).keydown(function(e){ var key = e.which; if (a==key) b=key; }); console.log(a+""+b); Whenever I try to

问题 I seem to be having circular dependency problems with using UserType inside AdType. This is my UserType file: UserType This is my AdType file: AdType If I try to use the code below I get the error "Ad.user field type must be Output Type but got: undefined" even tho I imported the UserType properly. import { UserType } from '../User/user.graphql.model' import { UserSchema } from '../User/user.mongoose.model' const user = { type: UserType, resolve(parentValue, args) { return UserSchema.findById