udid

问题 So I'm making an app where I want the users to be able add, edit and rate content, but I do not want to force them to register. Instead I was planning on just using their device id or device token to identify them. I'm planning on making both an iPhone and Android version, so I'm looking for a general solution, but the iPhone version has higher priority, so an iPhone specific solution would also be welcome. The problem is that I don't want just anyone to be able to use my web service by

问题 So I'm making an app where I want the users to be able add, edit and rate content, but I do not want to force them to register. Instead I was planning on just using their device id or device token to identify them. I'm planning on making both an iPhone and Android version, so I'm looking for a general solution, but the iPhone version has higher priority, so an iPhone specific solution would also be welcome. The problem is that I don't want just anyone to be able to use my web service by

问题 I am receiving the errors "No matching provisioning profiles found"[for your UDID], "The selected team doesn't have an iOS Developer Program membership" (Yes, it does. It's active.), and "Unable to create provisioning profile because your team has no devices registered in the Member Center. Please connect a device and enable it for development, and add it to the Member Center." (I already have an active provisioning profile in the Member Center.). When I try to register my Macbook as a

问题 Can someone tell me if the code I have been using is the proper way to get the unique id? I am suspecting i may have dupes out there and this could be causing issues on an administrative level in my company... final TelephonyManager tm = (TelephonyManager) context.getSystemService(Context.TELEPHONY_SERVICE); String UDID = tm.getDeviceId(); 回答1: It is the proper way to call getDeviceId() . That may not be a unique identifier, since not all devices are phones and some phones have bugs. See this

问题 Can someone tell me if the code I have been using is the proper way to get the unique id? I am suspecting i may have dupes out there and this could be causing issues on an administrative level in my company... final TelephonyManager tm = (TelephonyManager) context.getSystemService(Context.TELEPHONY_SERVICE); String UDID = tm.getDeviceId(); 回答1: It is the proper way to call getDeviceId() . That may not be a unique identifier, since not all devices are phones and some phones have bugs. See this

问题 Starting May 1st, 2013, Apple will stop accepting apps that access unique device identifiers (UDIDs) . Sounds like didRegisterForRemoteNotificationsWithDeviceToken: , will no longer get passed a UDID as the device token; but so far, this doesn't seem to be the case in iOS 6.0. To get around the issue and hedge the risk of my app getting rejected, I found this S.O. question , where they suggest using ASIdentifierManager to check if the user has enabled ad tracking for the app and then get the

问题 I know about iOS device UDID and that are case-sensitive. But I have a query, my client sent me all upper case in UDID characters. I have never seen any upper case letters in UDID's. I don't find any document that says UDID can have upper case letters consists. I need to create a right build to them. Could someone advise, what should I ask my client now? I can't say them, UDID is incorrect. Can I ask them to make sure the case-sensitive and send me back? Also, Can UDID have upper and lower

问题 I am getting different UDIDs for my iphone when i get it from itunes and programatically like this UDID:String = UIDevice.current.identifierForVendor!.uuidString Basically im trying to acquire a unique identifier for my iphone just like we have mac address for android phones. 回答1: one easiest way is to solve this issue by storing the identifierForVendor in keychain. even if you uninstall app ,value for the key remains same and its unchanged. many third party libraries available to perform

问题 Ad hoc testing facilities like TestFlight and HockeyApp use a part of the iOS OTA enrollment process to retrieve UDIDs (and possibly other device information, such as device type). How do these services achieve this? I've already figured out how to provide an initial "profile service" payload to send to the phone. I receive a valid response from the phone via a POSt request. After that, I'm clueless, I keep getting an "Invalid profile" error. What am I supposed to send back? Do I really have

问题 I am using the below code to get the android ID String android_id = Secure.getString(context.getContentResolver(), Secure.ANDROID_ID); I am able to get the android ID but it's length is not fixed. In some phones I get a 16 length ID and in other I get 15 length ID. I read in the documentation it is a 64 Hex decimal number so it should always return 16 digit string. So is there something wrong I am doing? 回答1: The following code snippet from AOSP shows how the ANDROID_ID is generated: