triangle

Fastest way to compute point to triangle distance in 3D?

匿名 (未验证) 提交于 2019-12-03 01:31:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: One obvious method for computing the minimum distance from a point to a 3D triangle is to project the point onto the plane of the triangle, determine the barycentric coordinates of the resulting point, and use them to determine whether the projected point lies within the triangle. If not, clamp its the barycentric coordinates to be in the range [0,1], and that gives you the closest point that lies inside the triangle. Is there a way to speed this up or simplify it somehow? 回答1: There are different approaches to finding the distance

Triangle UIView - Swift

匿名 (未验证) 提交于 2019-12-03 01:23:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: So I'm making a game in which I am dropping objects which have to be destroyed by a spike(triangle) at the bottom of the screen by a user. I cannot work out how to make a UIView that is a triangle. However I have been able to make it work as a rectangle like this: let barrier = UIView(frame: CGRect(x:125, y: 650, width: 130, height:20)) barrier.backgroundColor = UIColor.orangeColor() view.addSubview(barrier) And this has worked. But I cannot work out how to make a triangle. The reason I want it as a UIView is because im using collisions on

Gnuplot and Sierpinksi Triangle

匿名 (未验证) 提交于 2019-12-03 01:19:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: Question: I have a code, which hopefully makes a Sierpinski triangle, and I am wondering how can I output a data file that you read into gnuplot? I have never used gnuplot and I am trying to play around with it. Also, if that is not possible, how should I modify my code in order to plot my triangle so that I can see it? Explanation of code: I am trying to generate the Sierpinski triangle which starts at the point (0,0) and there is a 0.33 probablity that the next step will be halfway between the current point and (0,2) . There is a 0.33

Plotting only upper/lower triangle of a heatmap

匿名 (未验证) 提交于 2019-12-03 01:14:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: In maptplotlib, one can create a heatmap representation of a correlation matrix using the imshow function. By definition, such a matrix is symmetrical around its main diagonal, therefore there is no need to present both the upper and lower triangles. For example: The above example was taken from this site Unfortunately, I couldn't figure out how to do this in matplotlib. Setting upper/lower part of the matrix to None results in black triangle. I have googled for "matplotlib missing values", but couldn't find anything helpful 回答1: The problem

Java - draw a triangle [duplicate]

匿名 (未验证) 提交于 2019-12-03 01:12:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: This question already has an answer here: Triangle Draw Method 7 answers Hey I know that it is simple to draw oval/rectangle and fill it using g.fillOval(30, 40, 20, 20); but how to draw a triangle? It would be the best if it would have random coordinates. 回答1: There are at least two basics ways you can achieve this, based on your needs. You could use Polygon or you could make use the 2D Graphics Shape API Which you might choose comes down to your requirements. Polygon requires you to know, in advance the position of the points within 3D

Triangle : Determine whether a triangle can be built from a given set of edges

匿名 (未验证) 提交于 2019-12-03 01:05:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I have found a solution on the net for the codility problem below : A zero-indexed array A consisting of N integers is given. A triplet (P, Q, R) is triangular if 0 ≤ P < Q < R < N and: A[P] + A[Q] > A[R], A[Q] + A[R] > A[P], A[R] + A[P] > A[Q]. For example, consider array A such that: A[0] = 10 A[1] = 2 A[2] = 5 A[3] = 1 A[4] = 8 A[5] = 20 Triplet (0, 2, 4) is triangular. Write a function: int solution(int A[], int N); that, given a zero-indexed array A consisting of N integers, returns 1 if there exists a triangular triplet for this array

How to re-orient triangle faces in three.js

匿名 (未验证) 提交于 2019-12-03 01:02:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: * Edited with better example * I use Three.js to display the hull of an MRI gastric image; the hull is loaded from an external file as vtk format. Here is a demonstration: http://www.menne-biomed.de/uni/3d/alphahull.html ; use space to toggle. These are alpha-hulls computed from voxels as nicely three.js displayed in http://www.menne-biomed.de/uni/3d . I love these images. Thanks a log, Mr.doob!! Example 1-3 are from an almost empty stomach; 4-6 are from a filled stomach. (1) and (4) are single sided, to show that the triangles are

QOpenGLWidget Won&#039;t Draw Triangle

匿名 (未验证) 提交于 2019-12-03 00:44:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: So I'm trying to implement an editor for my game using Qt, and I can't seem to decipher how the QOpenGLWidget works. Right now, I just want to get a simple triangle to render, then I can worry about moving in all the rest of my stuff. Right now, it will open the window, and, in the QOpenGLWidget, will clear to the custom color I set in the subclass (so I did promote it), but it won't draw the triangle described in the class below. I've tried following the Qt OpenGLWindow example as well as the examples in QOpenGLWidget and

Pascal&#039;s Triangle

匿名 (未验证) 提交于 2019-12-03 00:37:01
numRows numRows In Pascal's triangle, each number is the sum of the two numbers directly above it. Example: Input: 5 Output: [ [1], [1,1], [1,2,1], [1,3,3,1], [1,4,6,4,1] ] class Solution { public: }; 文章来源: Pascal's Triangle

Pascal&#039;s Triangle #2解法

匿名 (未验证) 提交于 2019-12-03 00:30:01
题目如下: 构造一个帕斯卡三角/杨辉三角,并且是构建一个不规则的数组形式 已知帕斯卡三角/杨辉三角每一行第一个和最后一个元素为1,中间元素的值等于它上一行同一列的数值和上一行前一列的数值之和。 由此根据depth可分为三类: depth等于1,数组为【【1】】; depth等于2,数组为【【1】,【1,1】】; depth大于2,需要计算中间值。 代码如下: 文章来源: Pascal's Triangle #2解法